CODEWITHSUNDEEP
pythonmatlab
azal
azal

Reputation: 1260

How can i do this simple thing in Python from Matlab?

Simple Matlab code: e.g A(5+(1:3)) -> gives [A(6), A(7), A(8)]

In the above, A is a vector or a matrix. For instance:

A = [1 2 3 4 5 6 7 8 9 10];
A(5+(1:3)) 
ans =
     6    7    8

Note that MATLAB indexing starts at 1, not 0.

How can i do the same in Python?

Upvotes: 0

Views: 73

Answers (5)

Cory Kramer
Cory Kramer

Reputation: 117876

You are looking for slicing behavior

A = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

>>> A[5:8]
[6, 7, 8]

If A is some function that you want to call with parameters 6, 7, and 8, you could use a list comprehension.

answers = [A(6+i) for i in range(3)]

Upvotes: 3

Alex Shroyer
Alex Shroyer

Reputation: 3829

You want to do two things.

First, create a range (5 + (1:3)) which could be done in Python like range(number).

Second, apply a function to each range index. This could be done with map or a for loop.

The for loop solutions have been addressed, so here's a map based one:

result = map(A,your_range)

Upvotes: 1

Mujtaba Hasan
Mujtaba Hasan

Reputation: 112

in python u can do it easily by A[5:5+3] . u can reference the values 5 and 3 by variables also like b=5 c=3 a[b:b+c]

Upvotes: 0

M. K. Hunter
M. K. Hunter

Reputation: 1828

If you are trying to use subscripts to create an array which is a subset of the whole array: subset_list = A[6:8]

Upvotes: 0

Vincent Beltman
Vincent Beltman

Reputation: 2104

Use a list comprehension:

x = 5 
f = 1 # from
t = 3 # till
print [x+i for i in range(f,t+1)]

Upvotes: 0

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