CODEWITHSUNDEEP
javascriptjqueryajax
Revious
Revious

Reputation: 8156

Making a JQuery ajax request conditional

I would like to skip all this piece of code if some preconditions are not met, but I also want to move all the code between the parenthesis in a function. Is it allowed? I don't understand how this syntax works.

    $.ajax({
        type: "POST",
        url: urlAppend,
        data: JSON.stringify(xxx),
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        processdata: false,
        success: function (result) {
            if (canceled) {
                return;
            }
                //Long code
            }
        //Long code 2
        },
        error: function (request, error) {
            alert('ppp');
        }
    });

Upvotes: 0

Views: 8229

Answers (4)

CodeGodie
CodeGodie

Reputation: 12132

Try this: 

function runAjax(params){
    $.ajax({
        type: params["post"],
        url: params["url"],
        data: params["data"],
        contentType: params["content_type"],
        dataType: params["json"],
        processdata: params["process_bool"],
        success: function (result) {
            if (params["canceled"]) {
                return;
            }
                //Long code
            }
        //Long code 2
        },
        error: function (request, error) {
            alert('ppp');
        }
    });
}

if(condition){
  var options = {
      //set options here
  };
  runAjax(options);
}

Upvotes: 1

terales
terales

Reputation: 3200

Take a look at this sample:

function callAjax(condition) {
    if (condition) {
        $.ajax({
            type: "POST",
            url: urlAppend,
            data: JSON.stringify(xxx),
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            processdata: false,
            success: function (result) {
                if (canceled) {
                    return;
                }
                    //Long code
                }
            //Long code 2
            },
            error: function (request, error) {
                alert('ppp');
            }
        });
    }
}

// Somewhere in your code
callAjax(condition);

Upvotes: 1

Lucky Soni
Lucky Soni

Reputation: 6888

function doComplexStuff(){

} 

$.ajax({
        type: "POST",
        url: urlAppend,
        data: JSON.stringify(xxx),
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        processdata: false,
        success: doComplexStuff,
        error: function (request, error) {
            alert('ppp');
        }
    });

The doComplexStuff will automatically receive all the params that the success function receives.

Upvotes: 1

Lix
Lix

Reputation: 47986

Place your $.ajax call into a function, then wrap the call to the function in a conditional expression: 

function makeRequest(){
  $.ajax( ... )
}

if ( some_condition ){
  makeRequest();
}

Keep in mind that you are using some variables inside the AJAX callback (namely the canceled variable). You'll have to make that variable available to the function.

Upvotes: 5

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