CODEWITHSUNDEEP
pythonipv6scapyip-fragmentation
Ade
Ade

Reputation: 21

Scapy unable to fragment IPv6 packet

I am currently working on a project regarding IPv6 security. I'm trying to replicate the results found in this document found here: https://www.tno.nl/downloads/testing_the_security_of_IPv6_implementations.pdf

Scroll down to section 4.4, page 29.

I want to test whether creating packets with unlimited extension headers will in fact be able to crash a system. The problem I run in to again and again is that when running the script based on the documentation I keep getting the error:

File "/usr/lib/python2.7/dist-packages/scapy/packet.py", line 787, in fragment
   return Scapy_Exception("cannot fragment this packet")
scapy.error.Scapy_Exception: cannot fragment this packet

And I need the packets to be fragmented. Otherwise I will not be able to create this endless stream of extension headers. I am testing this on a Debian 7 Wheezy system and using Python 2.7.

Here is the script I'm running:

from scapy.all import *

packet = IPv6(src="scrIP",dst="dstIP")
for x in range (0,100):
    packet = packet/IPv6ExtHdrDestOpt()/IPv6ExtHdrRouting()/IPv6ExtHdrHopByHop()

    send(packet)

I have been searching around but I cannot find anything with the same error. I hope someone can help.

Upvotes: 1

Views: 3010

Answers (2)

Kristian A.
Kristian A.

Reputation: 1

There is something called scapy6:

http://www.secdev.org/conf/scapy-IPv6_HITB06.pdf

Try taking a look at page 128 and forward to see if you can get it to work, it should support IPv6.

Upvotes: 0

Klaus D.
Klaus D.

Reputation: 14379

You should check the version of scapy. The code work on my system (Ubuntu 14.04, scapy 2.2.0). Also try to run the code in the scapy shell as root:

$ sudo scapy 
Welcome to Scapy (2.2.0)
>>> p = IPv6(src='::1', dst='::1')
>>> for x in range(100): p = p/IPv6ExtHdrDestOpt()/IPv6ExtHdrRouting()/IPv6ExtHdrHopByHop()
... 
>>> send(p)
.
Sent 1 packets.

And of cause you have to replace scrIP and dstIP with real IPv6 adresses as strings.

Upvotes: 0

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