CODEWITHSUNDEEP
pythonimageopencv
Seppo
Seppo

Reputation: 199

How to find a pixel position with a given value

Example with a black pixel in the middle

What's the fastest way to find x and y coordinates of a pixel with a given rgb value? In this example the black pixel is at 100x100. Should I use openCV or Image? Does anyone have an idea or an example for me?

#!/usr/bin/env python
# coding: utf-8

import Image

img = Image.open('splash.png')
rgb = img.convert('RGB')
r, g, b = rgb.getpixel((100, 100))

print r, g, b
#for pixel in rgb.getdata():
#    print pixel
>>>0 0 0

As you can see I need the opposite way.

Upvotes: 1

Views: 7967

Answers (2)

Unapiedra
Unapiedra

Reputation: 16197

The only way to do this is to iterate through the complete image and stop when you found one pixel that matches your search. If you have to do it very often, for many different images, you can put them into a dictionary for faster access. 

import Image

def find_rgb(imagename, r_query, g_query, b_query):
    img = Image.open(imagename)
    rgb = img.convert('RGB')
    for x in range(img.size[0]):
       for y in range(img.size[1]):
           r, g, b, = rgb.getpixel((x, y))
           if r == r_query and g == g_query and b == b_query:
               return (x,y)

print(find_rgb('splash.png', 0, 0, 0))

Upvotes: 1

Mark Setchell
Mark Setchell

Reputation: 207365

Not sure whether you mean "short run time" or "quickest command to type". If you mean the latter, this took around 4 seconds to type using ImageMagick's convert command:

convert B7cjD.png txt: | grep "#000000"
100,100: (0,0,0,1)  #000000  black

Upvotes: 0

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