CODEWITHSUNDEEP
c++
jo1o3o
jo1o3o

Reputation: 61

Reverse Array in C++

I have successfully reversed a 1-D array but when I cout the contents, it prints out the contents then bunch of other numbers.

4
3
2
1
-858993460
-858993460
4
-858993460
-1021245226
12384668
3697177
1
14484784
14501672
-1021245434
0
Press any key to continue . . .

I can't tell why it's printing out those extra numbers. Below is my source code:

#include <iostream>
#include <array>

using namespace std;

void flipRow(int array[], int row) {
    int temp;
    for (int i = 0; i < sizeof(array)/2; i++) {
        //cout << "Hi" << endl;
        temp = array[i];
        array[i] = array[row-1];
        array[row-1] = temp;
        row--;
    }
}

int main() {

    const int ROW = 4;

    int array[ROW] = { 1, 2, 3, 4 };
    flipRow(array, ROW);

    for (int i = 0; i < sizeof(array); i++) {
        cout << array[i] << endl;
    }

    system("pause");
    return 0;
}

Are those addresses? Can someone tell why it's printing them out? Thank you.

Upvotes: 0

Views: 168

Answers (1)

DigitalEye
DigitalEye

Reputation: 1565

Modify your for loop in main so the condition part of it becomes i < ROW and modify the for loop in flipRow so the condition part there reads i < row/2. sizeof operator returns the size of your array in bytes. You have four elements in your array and they are of type integer, which on your platform is 4 bytes, so your call to sizeof is returning 16.

Upvotes: 1

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