Reputation: 123
I have a log file containing xml envelopes (2 types of xml structures: request and response). What i need to do is to parse this file, extract xml-s and put them into 2 arrays as strings (1st array for requests and 2nd array for responses), so i can parse them later.
Any ideas how can i achieve this in python ?
Snippet of log file to be parsed (log contains ):
2014-10-31 12:27:33,600 INFO Recharger_MTelemedia2Channel [mbpa.module.mgw.mtelemedia.mtbilling.MTSender][] Sending BILL request
2014-10-31 12:27:33,601 INFO Recharger_MTelemedia2Channel [mbpa.module.mgw.mtelemedia.mtbilling.MTSender][] <?xml version="1.0" encoding="UTF-8"?>
<request xmlns="XXX" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<transactionheader>
<username>XXX</username>
<password>XXX</password>
<time>31/10/2014 12:27:33</time>
<clientreferencenumber>123</clientreferencenumber>
<numberrequests>3</numberrequests>
<information>Description</information>
<postbackurl>http://localhost/status</postbackurl>
</transactionheader>
<transactiondetails>
<items>
<item id="1" client="XXX1" keyword="test"/>
<item id="2" client="XXX2" keyword="test"/>
<item id="3" client="XXX3" keyword="test"/>
</items>
</transactiondetails>
</request>
2014-10-31 12:27:34,487 INFO Recharger_MTelemedia2Channel [mbpa.module.mgw.mtelemedia.mtbilling.MTSender][] Response code 200 for bill request
2014-10-31 12:27:34,489 INFO Recharger_MTelemedia2Channel [mbpa.module.mgw.mtelemedia.mtbilling.MTSender][] <?xml version="1.0" encoding="UTF-8"?>
<response xmlns="XXX" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<serverreferencenumber>XXX123XXX</serverreferencenumber>
<clientreferencenumber>123</clientreferencenumber>
<information>Queued for Processing</information>
<status>OK</status>
</response>
Many thanks for reply!
Regards, Robert
Upvotes: 1
Views: 4615
Reputation: 20563
As both @Paco and @Lord_Gestalter suggested, you can use xml.etree
and replace the non-XML elements from your file, something like this:
# I use re to substitute non-XML elements
import re
# then use xml module as a parser
import xml.etree.ElementTree as ET
# read your file and store in string 's'
with open('yourfilehere','r') as f:
s = f.read()
# then remove non-XML element with re
# I also remove <?xml ...?> part as your file consists of multiple xml logs
s = re.sub(r'<\?xml.*?>', '', ''.join(re.findall(r'<.*>', s)))
# wrap your s with a root element
s = '<root>'+s+'</root>'
# parse s with ElementTree
tree = ET.fromstring(s)
tree
<Element 'root' at 0x7f2ab877e190>
if you don't care about xml parser and just want 'request' & 'response' string, use re.search
with open('yourfilehere','r') as f:
s = f.read()
# put the string of both request and response into 'req' and 'res'
# or you need to construct a better re.search if you have multiple requests, responses
req = [re.search(r'<request.*\/request>', s).group()]
res = [re.search(r'<response.*\/response>', s).group()]
req
['<request xmlns="XXX" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><transactionheader><username>XXX</username><password>XXX</password><time>31/10/2014 12:27:33</time><clientreferencenumber>123</clientreferencenumber><numberrequests>3</numberrequests><information>Description</information><postbackurl>http://localhost/status</postbackurl></transactionheader><transactiondetails><items><item id="1" client="XXX1" keyword="test"/><item id="2" client="XXX2" keyword="test"/><item id="3" client="XXX3" keyword="test"/></items></transactiondetails></request>']
res
['<response xmlns="XXX" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><serverreferencenumber>XXX123XXX</serverreferencenumber><clientreferencenumber>123</clientreferencenumber><information>Queued for Processing</information><status>OK</status></response>']
Upvotes: 2