CODEWITHSUNDEEP
javascriptregex
brinch
brinch

Reputation: 2614

How to find the string that matches in array?

I would like to get the full string element from an array that matches multiple substrings in no particular order. If more than one match, an exception should be thrown.

var thisArray = [ '/something_else/', '/and_something_else/', '/and_something_else_here/'];
var thisMatch = [ 'some', 'and', 'here'];

var matchingElement = new RegExp(thisArray , thisMatch); // Not sure about this

What I want is for matchineElement to contain the string "and_something_else_here" after the regular expression has executed.

Upvotes: 0

Views: 83

Answers (4)

StackSlave
StackSlave

Reputation: 10617

Take those slashes off of both sides of your Strings in those Arrays. Then use the arrayMatch function below, and loop over your indexes to get the results of thisArray, like:

function arrayMatch(yourArray, wordMatchArray){
  var ix = [], c = wordMatchArray.length;
  for(var i=0,l=yourArray.length; i<l; i++){
    var m = 0;
    for(var n=0; n<c; n++){
      if(yourArray[i].match(new RegExp(wordMatchArray[n])))m++;
      if(c === m)ix.push(i);
    }
  }
  if(!ix[0]){
    return false;
  }
  return ix;
}
var indexes = arrayMatch(thisArray, thisMatch);
for(var i=0,l=indexes.length; i<l; i++){
  var getMatch = thisArray[indexes[i]];
}

Upvotes: 0

guest271314
guest271314

Reputation: 1

Try

var matchingElement = thisArray.filter(function(val, key) {
 var value = val.split(/[^a-z]/).filter(String).join(" ");
 // if `.test()` returns `true` three times at `value`
 return new RegExp(this[0]).test(value) 
        && new RegExp(this[1]).test(value) 
        && new RegExp(this[2]).test(value) 
        ? val
        : null
}.bind(thisMatch))[0].replace(/\//g,"");)


var thisArray = [ '/something_else/', '/and_something_else/', '/and_something_else_here/'];
var thisMatch = [ 'some', 'and', 'here'];

var matchingElement = thisArray.filter(function(val, key) {
 var value = val.split(/[^a-z]/).filter(String).join(" ");
 // if `.test()` returns `true` three times at `value`
 return new RegExp(this[0]).test(value) 
        && new RegExp(this[1]).test(value) 
        && new RegExp(this[2]).test(value) 
        ? val
        : null
}.bind(thisMatch))[0].replace(/\//g,"");

document.write(matchingElement)

Upvotes: 0

strah
strah

Reputation: 6742

You could do something like this:

var thisArray = [ '/something_else/', '/and_something_else/', '/and_something_else_here/'];
var thisMatch = [ 'some', 'and', 'here'];

function matchElements(arr, arrMatch) {
    var tmpArr;
    arrMatch.forEach(function(el, i, a) {
        tmpArr = arr.filter(function(str) {
            return str.indexOf(el) !== -1;
        });
    });
    if (tmpArr.length > 1) {
        throw ("Hey, too many matches");
    } else {
        return tmpArr[0];   
    }
}

console.log(matchElements(thisArray, thisMatch));

JSFiddle: http://jsfiddle.net/Le53y7ee/

Explanation:

The function goes through every element in the array containing substrings and filters main array keeping only strings that match. After the loop is done the array should contain only string(s) that matched all required substrings.

Upvotes: 2

Barmar
Barmar

Reputation: 782785

A regexp that matches a string containing all of a set of substrings looks like:

^(?=.*?string1)(?=.*?string2)(?=.*?string3).*$

So you just need to convert your thisMatch array into such a regular expression.

var regexp = new RegExp('^' + thisMatch.map(function(x) {
    return '(?=.*?' + x + ')';
}).join('') + '.*$');

Then you can find all the matches with:

var matchingElements = thisArray.filter(function(x) {
    return regexp.test(x);
});

if (matchingElements.length != 1) {
    throw new Error('Single match not found');
} else {
    matchingElement = matchingElements[0];
}

DEMO

Upvotes: 1

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