CODEWITHSUNDEEP
cobfuscation
noob
noob

Reputation: 231

How does this "hello world!" program work?

int main(void)
{ 
    return('yes', *"no", **main, *********printf) ("hello world!\n") *0; 
}

outputs hello world!, but how does it actually work?

Upvotes: 23

Views: 1902

Answers (2)

el.pescado - нет войне
el.pescado - нет войне

Reputation: 19236

('yes', *"no", **main, *********printf)

will evaluate to *********printf, because comma operator evaluates its operands and returns value of last expression. *********printf is equal to printf, as dereferencing function pointer results in the same function pointer; it does nothing.

Next, result of first parenthesis, printf, is applied to ("hello world!\n") which results in text printed to screen. printf function returns number of characters written. That number is then multiplied with 0 and product is returned by main function.

Upvotes: 12

rampion
rampion

Reputation: 89123

Two things really:

  1. Function pointers don't dereference the same as other pointers. *main == main
  2. A comma separated list returns the value of the last element in the list

So if we simplify the pointers:

int main(void)
{ 
    return('yes', *"no", main, printf) ("hello world!\n") *0; 
}

And using the last element in the list as the value of the list

int main(void)
{ 
    return printf("hello world!\n") *0; 
}

printf returns the number of characters printed

int main(void)
{ 
    return 13 *0; 
}

And 13*0 is left as an exercise to the reader.

Upvotes: 46

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