CODEWITHSUNDEEP
php
Stephen Kennedy
Stephen Kennedy

Reputation: 549

PHP Array breaking

This works on my test environment, but on my live server there is a later version of PHP which is throwing up an error and breaking my program

The code is

$oldFile = fopen("D:/ftpfolderreport/report/" . $last_file, "r");
while(!feof($oldFile))
{
$buffler = fgets($oldFile);
$bufflerArray = explode(",", $buffler);
$key = $bufflerArray[0];
$oldFileArray[$key] = $bufflerArray[1];
}
fclose($oldFile);

This line: 

$oldFileArray[$key] = $bufflerArray[1];

Is throwing out this error

Notice: Undefined offset: 1 in D:\apps\wamp\www\Compliance2\compareFtpReports.php on line 57

I think this is to do with how I'm adding the $key variable inside the argument. I've tried it as ["$key"] and ['$key'] but it doesn't like it.

I have tried defining the key variable earlier in the program but still doesn't like it. I've been searching around online but can't find anything of help. Anyone any ideas?

Thanks, Stephen.

Upvotes: 0

Views: 58

Answers (1)

Sougata Bose
Sougata Bose

Reputation: 31749

add checks for empty

if (!empty($bufflerArray[1])) {
   $key = $bufflerArray[0];
   $oldFileArray[$key] = $bufflerArray[1];
}

Upvotes: 1

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