CODEWITHSUNDEEP
javaregexregex-group
Levi
Levi

Reputation: 175

separate the two matches

Regex problem: I want to get groups twice, but don't know how to solve it.

Here is code:

public static void multiGroupTest() {
    // Pattern p = Pattern.compile("(\\w+)(\\d\\d)(\\w+)");
    Pattern p = Pattern.compile("([A-Z]{1})(\\d+)([A-Za-z]+)");
    String str = "X89SuperJavaJavaX89SuperJava";
    Matcher m = p.matcher(str);
    while (m.find()) {
        System.out.println(m.group(1));
        System.out.println(m.group(2));
        System.out.println(m.group(3));
    }
}

OK, the result is:

X
89
SuperJavaJavaX

What i want to get is:

X
89
SuperJavaJava
X
89
SuperJava

How can I separate the two matches?

Upvotes: 3

Views: 58

Answers (3)

Avinash Raj
Avinash Raj

Reputation: 174706

Because the last group ([A-Za-z]+) would greedily match the following X , you didn't able to get two strings. Use ((?:[A-Z][a-z]+)+) to capture the words which are in this FooBar format. Because names wouldn't end with a capital letter.

([A-Z])(\\d+)((?:[A-Z][a-z]+)+)

DEMO

Pattern p = Pattern.compile("([A-Z])(\\d+)((?:[A-Z][a-z]+)+)");
String str = "X89SuperJavaJavaX89SuperJava";
Matcher m = p.matcher(str);
while (m.find()) {
    System.out.println(m.group(1));
    System.out.println(m.group(2));
    System.out.println(m.group(3));
}

Output:

X
89
SuperJavaJava
X
89
SuperJava

Upvotes: 1

vks
vks

Reputation: 67968

([A-Z]{1})(\d+)((?:(?!\1)[a-zA-Z])+)

Try this.See demo.

http://regex101.com/r/sU3fA2/59

Upvotes: 0

Mena
Mena

Reputation: 48404

Change your Pattern to add a negative lookahead for the digit:

Pattern p = Pattern.compile("([A-Z]{1})(\\d+)([A-Za-z]+)(?!\\d)");
String str = "X89SuperJavaJavaX89SuperJava";

Output

X
89
SuperJavaJava
X
89
SuperJava

Upvotes: 3

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