Reputation: 14921
I have a list of items in a generic list:
The comparator on them takes the form:
this.sortIndex.CompareTo(other.sortIndex)
When I do a List.Sort() on the list of items, I get the following order out:
It has obviously worked in the sense that the sort indexes are in the right order, but I really don't want it to be re-ordering the 'B' items.
Is there any tweak I can make to my comparator to fix this?
Upvotes: 4
Views: 1856
Reputation: 57220
Sort uses QuickSort, and it doesn't assure original sequence in case of comparison equality.
If you still want to use List.Sort you could add a second comparison with the original index like:
int c = this.sortIndex.CompareTo(other.sortIndex);
if (c == 0)
c = this.originalIndex.CompareTo(other.originalIndex);
return c;
otherwise you can sort with other "stable" algorithms (e.g. LINQ OrderBy).
Upvotes: 1
Reputation: 129802
OrderBy
preserves order for equal items:
myList = myList.OrderBy(item => item.SortIndex).ToList();
Upvotes: 5
Reputation: 499172
You can change your comparator to do a secondary sort on the value:
if (this.sortIndex.CompareTo(other.sortIndex) == 0) // same sortIndex
{
return this.Value.CompareTo(other.Value);
}
return 0;
Upvotes: 1
Reputation: 49512
you need to use a "stable sort" algorithm if you don't want items that are equal to change position.
Check out "merge sort" for an example of a stable sort algorithm. Here's an implementation of it in C#.
Upvotes: 5