CODEWITHSUNDEEP
javastringcharacteroperation
user4216497
user4216497

Reputation:

Operation on character in java

i have this method : 

public static String appliquerCoup( String combinaison, String coup ){
    String res = "";
    for(int i = 0; i < 3; i++){
        res = res + (combinaison.charAt(i) - coup.charAt(i));
    }
    return res;
}

if i apply this in the main

System.out.println(appliquerCoup("414", "020")

i have :

4-14

As logical as it is, it's puting me a -1 for 2-1 = -1 I want it to put me 0 if the operation is inferior to 0.

So i made these changes :

public static String appliquerCoup( String combinaison, String coup ){
    String res = "";
    for(int i = 0; i < 3; i++){
        char cFinal = combinaison.charAt(i) - coup.charAt(i);
        if(cFinal < '0')
        cFinal = 0;
        res = res + cFinal;
    }
    return res;
}

but it is saying me that on the 4th line that there's

possible loss of precision
found :int; required: char

Can you help me find the solution ? It's been a long i'm trying.

Thanks so much

Upvotes: 1

Views: 117

Answers (1)

khelwood
khelwood

Reputation: 59112

The result of subtracting one character from another is an integer. It tells you the distance between them.

Imagine you were calculating 'b' - 'a'. The difference between them is the number 1, not the character '1'.

You can change cFinal to an int and it should work, since it's legal to append integers to a string:

int cFinal = combinaison.charAt(i) - coup.charAt(i);
if (cFinal < 0) // NB: compare with 0, not '0'
    cFinal = 0;
res = res + cFinal;

Or you can use max to enforce the lower bound more succinctly.

res += Math.max(0, combinaison.charAt(i) - coup.charAt(i));

Upvotes: 1

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