CODEWITHSUNDEEP
matlabplotmatlab-figure
David
David

Reputation: 1021

Using meshz command in Matlab

I've done the following code:

u=linspace(0,1,40);
v=linspace(0,1,40);
[u,v]=meshgrid(u,v);
x=u;
y=v.*sqrt(u);
z=x+y+1;
meshz(x,y,z)
xlabel('x-axis')
ylabel('y-axis')

Which gives the following image:

enter image description here

Now, I'd like to decrease the mesh walls down to the x-y-plane (at z=0). I tried the following, which did not work:

u=linspace(0,1,40);
v=linspace(0,1,40);
[u,v]=meshgrid(u,v);
x=u;
y=v.*sqrt(u);
z=x+y+1;
meshz(x,y,z)
xlabel('x-axis')
ylabel('y-axis')
v=axis;
v(5)=0;
axis(v)

which yields the following picture:

enter image description here

I tried a couple of other things, like the last code: adding hold on, calling meshz(x,y,z) again, but they did not work. How I can extend the meshz walls down to the x-y-plane?

Upvotes: 2

Views: 340

Answers (1)

horchler
horchler

Reputation: 18504

One way to do this is to directly manipulate the 'ZData' produced by meshz via some handle graphics:

...
h = meshz(x,y,z);   % Get handle
Z = get(h,'ZData'); % Get ZData
Z([1 end],:) = 0;   % Set border to 0, or other desired value
Z(2:end-1,[1 end]) = 0;
set(h,'ZData',Z);   % Set ZData
...

which produces

enter image description here

Upvotes: 3

Related Questions