CODEWITHSUNDEEP
pythondictionary
Zlo
Zlo

Reputation: 1170

Selecting values from python dictionaries and string into new dicts

I have sorted map that stores keys and values of a dict:

def sorted_map(map):
ms = sorted(map.iteritems(), key=lambda (k,v): (-v,k)) 
return ms

It stores the network nodes as keys, and their degrees as values – the output is like this:

for line in ms:
    print  line


('Node n', 11)
('Node n+1', 11)
('Node n+2', 11)

Values range from ~ 1000 through 0. I need to only select those nodes (keys) that have a value of higher/equal to 10. And preferably store them into a new dict (key:value). Is there a way to do it?

Upvotes: 0

Views: 118

Answers (2)

aseeon
aseeon

Reputation: 323

dict comprehension from Padraic is a better solution, but just to see what is out there you can use filter and dict functions:

def sorted_map(dictionary):
    ms = sorted(dictionary.iteritems(), key=lambda (k, v): (-v, k))
    return ms

star_map = {
    'Node 1': 11,
    'Node 2': 12,
    'Node 3': 9,
}

filtered = filter(lambda x: x[1] >= 10, sorted_map(star_map))

print(dict(filtered))

Note: You should not use map as a variable name because this is a built-in function.

Upvotes: 1

Padraic Cunningham
Padraic Cunningham

Reputation: 180482

Just create a new dict from your original dict items, keeping key/value pairings that have a value >= 10 

d = {1:23,2:20,3:10,4:9,5:1}
print({k:v for k,v in d.items() if v >=10})
{1: 23, 2: 20, 3: 10}

If you just want a new dict sorting is not required.

Upvotes: 2

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