Reputation: 653
I have an array X that I'd like to convert to a dataframe. Upon recommendation from the web, I tried converting to a dataframe and get the following error.
julia> y=convert(DataFrame,x)
ERROR:
converthas no method matching convert(::Type{DataFrame}, ::Array{Float64,2})
in convert at base.jl:13
When I try DataFrame(x)
, the conversion works but i get a complaint that the conversion is deprecated.
julia> DataFrame(x)
WARNING: DataFrame(::Matrix, ::Vector)) is deprecated, use convert(DataFrame, Matrix) instead in DataFrame at /Users/Matthew/.julia/v0.3/DataFrames/src/deprecated.jl:54 (repeats 2 times)
Is there another method I should be aware of to keep my code consistent?
EDIT: Julia 0.3.2, DataFrames 0.5.10 OSX 10.9.5
julia> x=rand(4,4)
4x4 Array{Float64,2}:
0.467882 0.466358 0.28144 0.0151388
0.22354 0.358616 0.669564 0.828768
0.475064 0.187992 0.584741 0.0543435
0.0592643 0.345138 0.704496 0.844822
julia> convert(DataFrame,x)
ERROR: `convert` has no method matching convert(::Type{DataFrame}, ::Array{Float64,2}) in convert at base.jl:13
Upvotes: 11
Views: 24477
Reputation: 907
Since this is the first thing that comes up when you google, for more recent versions of DataFrames.jl
, you can just use the DataFrame()
function now:
julia> x = rand(4,4)
4×4 Matrix{Float64}:
0.920406 0.738911 0.994401 0.9954
0.18791 0.845132 0.277577 0.231483
0.361269 0.918367 0.793115 0.988914
0.725052 0.962762 0.413111 0.328261
julia> DataFrame(x, :auto)
4×4 DataFrame
Row │ x1 x2 x3 x4
│ Float64 Float64 Float64 Float64
─────┼────────────────────────────────────────
1 │ 0.920406 0.738911 0.994401 0.9954
2 │ 0.18791 0.845132 0.277577 0.231483
3 │ 0.361269 0.918367 0.793115 0.988914
4 │ 0.725052 0.962762 0.413111 0.328261
Upvotes: 9
Reputation: 31
A little late, but with the update to the DataFrame() function, I created a custom function that would take a matrix (e.g. an XLSX imported dataset) and convert it into a DataFrame using the first row as column headers. Saves me a ton of time and, hopefully, it helps you too.
function MatrixToDataFrame(mat)
DF_mat = DataFrame(
mat[2:end, 1:end],
string.(mat[1, 1:end])
)
return DF_mat
end
Upvotes: 2
Reputation: 11
DataFrame([1 2 3 4; 5 6 7 8; 9 10 11 12], :auto)
This works as per >? DataFrame
Upvotes: 1
Reputation: 11
So I found this online and honestly felt dumb.
using CSV
WhatIWant = DataFrame(WhatIHave)
this was adapted from an R guide, but it works so heck
Upvotes: 1
Reputation: 4127
# convert a Matrix{Any} with a header row of col name strings to a DataFrame
# e.g. mat2df(["a" "b" "c"; 1 2 3; 4 5 6])
mat2df(mat) = convert(DataFrame,Dict(mat[1,:],
[mat[2:end,i] for i in 1:size(mat,2)]))
# convert a Matrix{Any} (mat) and a list of col name strings (headerstrings)
# to a DataFrame, e.g. matnms2df([1 2 3;4 5 6], ["a","b","c"])
matnms2df(mat, headerstrs) = convert(DataFrame,
Dict(zip(headerstrs,[mat[:,i] for i in 1:size(mat,2)])))
Upvotes: 2
Reputation: 41
I've been confounded by the same issue a number of times, and eventually realized the issue is often related to the format of the array, and is easily resolved by simply transposing the array prior to conversion.
In short, I recommend:
julia> convert(DataFrame, x')
Upvotes: 4
Reputation: 9676
This works for me:
julia> using DataFrames
julia> x = rand(4, 4)
4x4 Array{Float64,2}:
0.790912 0.0367989 0.425089 0.670121
0.243605 0.62487 0.582498 0.302063
0.785159 0.0083891 0.881153 0.353925
0.618127 0.827093 0.577815 0.488565
julia> convert(DataFrame, x)
4x4 DataFrame
| Row | x1 | x2 | x3 | x4 |
|-----|----------|-----------|----------|----------|
| 1 | 0.790912 | 0.0367989 | 0.425089 | 0.670121 |
| 2 | 0.243605 | 0.62487 | 0.582498 | 0.302063 |
| 3 | 0.785159 | 0.0083891 | 0.881153 | 0.353925 |
| 4 | 0.618127 | 0.827093 | 0.577815 | 0.488565 |
Are you trying something different?
If that doesn't work try posting a bit more code we can help you better.
Upvotes: 10