CODEWITHSUNDEEP
phpmysql
ambe5950
ambe5950

Reputation: 75

Dynamic link inside a dynamic PHP table

So I have a dynamic PHP table where I am trying echo one of the table columns as a dynamically generated link. Presently, the $url variable i have declared is returning null. $row['username'] is returning what it should, so I suspect I have the syntax off for that. I also am having trouble with the syntax on the following line. How do I insert the $row['username'] as the link text? 

echo "<td>" . "<a href='".$url."'> . $row['username'] .  </a>" . "</td>";

this present example returns an error, but when I replace it with:

echo "<td>" . "<a href='".$url."'> blahblahfiller </a>" . "</td>";

the page runs, so I know it's my syntax there.

Here is my full code for the table:

<?php
   while ($row = mysql_fetch_array($query)) {
        $url = "profilepage.php?name=" + $row['username'];
        echo "<tr>";
        echo "<td>" . '<input type="checkbox" name="checkbox"/>' . "</td>";
        echo "<td>" . "<a href='".$url."'> . $row['username'] .  </a>" . "</td>";
        echo "<td>" . $row['gender'] . "</td>";
        echo "<td>" . $row['username'] . "</td>";
        echo "<td>" . $url . "</td>";
        echo "</tr>";
   }
?>

Sincere thanks for any and all help! It means a lot.

Upvotes: 0

Views: 414

Answers (1)

Sougata Bose
Sougata Bose

Reputation: 31739

You are using + instead of . for to concatenate. It should be - 

$url = "profilepage.php?name=". $row['username'];

Upvotes: 1

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