CODEWITHSUNDEEP
pythonlistfor-loopwhile-loopcounter
bngschmnd
bngschmnd

Reputation: 111

PYTHON: Print X items of a list

I have this code:

U = [1,2,3,4,5,6,7,8,9,10,11,12]

def bla(anzahl):
    zaehlwerk = 0
    while zaehlwerk < anzahl:
        for x in U:
            zaehlwerk = zaehlwerk +1
            print x

my query:

bla(3)

I hoped that now I would get the first 3 list items, but instead I get the whole list.

1
2
3
4
5
6
7
8
9
10
11
12

I tried to debug because I thought that maybe the counter wouldn't work, but it does. But then where is my error?

Upvotes: 0

Views: 5085

Answers (2)

Hackaholic
Hackaholic

Reputation: 19743

use slicing :

>>> U = [1,2,3,4,5,6,7,8,9,10,11,12]
>>> U[:3]
[1, 2, 3]

U[stat-index:end-index], you will get element from start-index to one less end-index, as in above example

>>>U[2:6]
[3, 4, 5, 6]

what you need to do is this using slicing:

def print_list(n):
    print "\n".join(map(str,U[:n]))
print_list(3)

output:

1
2
3

Upvotes: 6

KirkSpaziani
KirkSpaziani

Reputation: 1972

for x in U:

is the innermost loop. That is making sure you iterate over everything.

As is you can modify your code to look like

def bla(anzahl):
    zaehlwerk = 0
    while zaehlwerk < anzahl:
        x = U[zaehlwerk]
        zaehlwerk = zaehlwerk +1
        print x

And that will work for what you want. But more concise would be to to use something like

for index in range(len(anzahl)):
    print U[index]

Upvotes: 0

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