Santhosh Pai
Santhosh Pai

Reputation: 2625

Parsing Json string through command line

I'm new to php and Json and i'm trying to decode the command line Json strings , but the Json decode function gives null while decoding , i'm sending the data in the correct format not sure why it is going wrong .I have checked with the threads and the passing the data as per the url http://php.net/manual/en/function.json-decode.php .

Here is my code

<? php

if($argc==2)
{
    $jsonin=$argv[1];

    echo $jsonin."\xA";

    $jsonin="'".$jsonin."'";

    echo $jsonin ."\xA";

    $cmdval=json_decode($jsonin);


    if($cmdval)
    {
       echo $cmdval->{'id'};
    }
    else
    {
        echo "Bad string" ; 
    }



}
else
{
   echo "No arguments";
}


?>

This is how i'm passing it to the code

php5 jsonparse.php '{ "time1":"2014/10/30 21:30:00", "time2":"2014/10/31 21:30:00" }'

following are the outputs

 {  "time1":"2014/10/30 21:30:00", "time2":"2014/10/31 21:30:00"}

'{ "time1":"2014/10/30 21:30:00", "time2":"2014/10/31 21:30:00"}'

Bad string

Upvotes: 0

Views: 182

Answers (2)

OnlyMAJ
OnlyMAJ

Reputation: 819

I have tried this and it works like a charm :

if($argc==2)
{
    $jsonin=$argv[1];
    $cmdval=json_decode($jsonin);
    if($cmdval)
    {
        echo "You did it right !\r\n";
        print_r($cmdval);
    }
    else
    {
        echo "Bad string" ; 
    }
}
else
{
   echo "No arguments";
}

And i ran it as below:

php test.php '{ "time1":"2014/10/30 21:30:00", "time2":"2014/10/31 21:30:00" }'

Upvotes: 1

Akshay Vanjare
Akshay Vanjare

Reputation: 655

Why you are doing this? $jsonin="'".$jsonin."'";
Please remove this code and try again.

Upvotes: 1

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