Reputation: 694
I have a view in Django which calls external library/class. The problem is that for some reason Django keeps caching results coming from previous calls of that class.
Please consider the following simple example:
Django view:
from some_path import Demo
def test_view(request):
demo = Demo()
result = demo.do_something()
return render(request, 'test.html',
{ 'result':result }
)
Demo class:
class Demo():
result = []
def do_something(self):
self.result.append(1)
self.result.append(2)
self.result.append(3)
return self.result
You expect result to be [1, 2, 3], right ? WRONG!
The first time a page is loaded you'll get the correct result. But on all following requests it will keep incrementing: [1, 2, 3, 1, 2, 3]... [1, 2, 3, 1, 2, 3, 1, 2, 3] ...
So my question is obvious - what is going on here ? How do i receive [1, 2, 3] every time i call a class inside Django view ?
Django 1.7 / MacOS X.
Upvotes: 0
Views: 127
Reputation: 5275
"""
Case 1:
Here we have declared the result and some_string as static Class variable
"""
class Demo_1():
result = []
some_string = ""
def do_something(self):
Demo_1.some_string = Demo_1.some_string + "Python "
self.result.append(1)
self.result.append(2)
self.result.append(3)
return self.result
demo = Demo_1()
print Demo_1.result
result = demo.do_something()
print Demo_1.result
demo = Demo_1()
result = demo.do_something()
print Demo_1.result
demo = Demo_1()
result = demo.do_something()
print Demo_1.result
print result
print demo.some_string
print "Demo_1 class attributes :-", dir(Demo_1)
"""
Case1 Output :
[]
[1, 2, 3]
[1, 2, 3, 1, 2, 3]
[1, 2, 3, 1, 2, 3, 1, 2, 3]
[1, 2, 3, 1, 2, 3, 1, 2, 3]
Python Python Python
Demo_1 class attributes :- ['__doc__', '__module__', 'do_something', 'result', 'some_string']
As you can see both result and some_string exists in Demo_1's attributes
which you can access by both by Class name as well as it's instance
"""
print "-----------------------------------------------------------------"
"""
Case 2:
Here we have declared the result variable as Class instance variable.
So each time we create an instance of class it creates new memory for that instance.
"""
class Demo_2():
def __init__(self):
self.result = []
self.some_string = " "
def do_something(self):
self.result.append(1)
self.result.append(2)
self.result.append(3)
return self.result
demo = Demo_2()
result = demo.do_something()
print demo.result
demo = Demo_2()
result = demo.do_something()
print demo.result
demo = Demo_2()
result = demo.do_something()
print demo.result
print result
print "Demo_1 class attributes :-", dir(Demo_2)
print Demo_2.some_string
"""
Case2 Output :
[1, 2, 3]
[1, 2, 3]
[1, 2, 3]
[1, 2, 3]
Demo_1 class attributes :- ['__doc__', '__init__', '__module__', 'do_something']
Traceback (most recent call last):
File "bl.py", line 83, in <module>
print Demo_2.some_string
AttributeError: class Demo_2 has no attribute 'some_string'
As you can see Class Demo_2 has no attributes result or some_string as
they are instance variable.
"""
See more about static Class variable Here
Upvotes: 0
Reputation: 5061
Define result
in __init__
as an instance attribute.
class Demo():
def __init__(self):
self.result = []
def do_something(self):
self.result.append(1)
self.result.append(2)
self.result.append(3)
return self.result
If you print result
in your code then you will get that result
is assigning just once,
class Demo():
result = []
print result
def ...
.
.
d = Demo()
print d.do_something()
print d.do_something()
e = Demo()
print e.do_something()
>>>
[]
[1, 2, 3]
[1, 2, 3, 1, 2, 3]
[1, 2, 3, 1, 2, 3, 1, 2, 3]
result
is a mutable object, whenever you made an instance of the class it refer result
to the same reference.
In case of Immutable object:-
class Demo():
result = 1
def do_something(self):
self.result += 1
d = Demo()
d.do_something()
d.do_something()
e = Demo()
e.do_something()
print d.result, e.result
Output:-
>>>
3 2
Upvotes: 10
Reputation: 13943
Why don't you try initializing the result=[]
inside your do_something
method something like this ?
def do_something(self):
result = []
result.append(1)
result.append(2)
result.append(3)
return result
Upvotes: 1