CODEWITHSUNDEEP
bash
onur
onur

Reputation: 6365

How can I check lines in file with bash

I have a log file like this:

 20141107 14:15:02;10.0.0.5;/home/it/17066.txt;0
 20141107 14:15:32;10.0.0.5;/home/it/17076.txt;0
 20141107 14:16:15;10.0.0.5;/home/it/17086.txt;0
 ...

My bash script parsing big log file and create new small log files. Script check small log file and if does not exist, create:

if [ ! -f "$path/$name" ]; then

mkdir -p "$path"
touch "$path/$name"
echo "$year$month$day $time;$ip;$file;$size" >> "$path/$name"

fi

If the log file is exist, I want to write into that file. I try this:

if [ ! -f "$path/$name" ]; then

mkdir -p "$path"
touch "$path/$name"
echo "$year$month$day $time;$ip;$file;$size" >> "$path/$name"

else 
echo "$year$month$day $time;$ip;$file;$size" >> "$path/$name"
fi

It's working if file exist or not. But writing same lines in log file:

 20141107 14:15:02;10.0.0.5;/home/it/17066.txt;0
 20141107 14:15:32;10.0.0.5;/home/it/17076.txt;0
 20141107 14:16:15;10.0.0.5;/home/it/17086.txt;0
 20141107 14:15:02;10.0.0.5;/home/it/17066.txt;0
 20141107 14:15:32;10.0.0.5;/home/it/17076.txt;0
 20141107 14:16:15;10.0.0.5;/home/it/17086.txt;0
 ...

I need to do if line does exist in log file, write. If line exist in log file, skip.

How can I do?

Upvotes: 0

Views: 77

Answers (2)

John Zwinck
John Zwinck

Reputation: 249113

str="$year$month$day $time;$ip;$file;$size"
if ! grep -q "^$str$" "$path/$name"; then
    echo "$year$month$day $time;$ip;$file;$size" >> "$path/$name"
fi

Note that this is not efficient if the output file becomes large.

Upvotes: 1

codebox
codebox

Reputation: 20254

Why not just do this:

if [ ! -f "$path/$name" ]; then
    mkdir -p "$path"
    touch "$path/$name"
fi
echo "$year$month$day $time;$ip;$file;$size" >> "$path/$name"

Upvotes: 0

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