CODEWITHSUNDEEP
pythonxmlxml-parsinglxml
trinchet
trinchet

Reputation: 6933

Why etree.find doesn't find the element for the provided example

Lets suppose it has this:

xml_as_str = '''
<v1:Header>
    <v2:Person>Foo Bar</v2:Person>
    <v2:Email>[email protected]</v2:Email>
</v1:Header>
'''

from lxml import etree
tree = etree.fromstring(xml_as_str, etree.XMLParser(recover=True))

How could it get the value of certain tag, e.g "Foo Bar" for v2:Person ?

I've tried this:

 >> tree.find('.//v2:Person')
 >> tree.find('.//{Person}v2')

in order to get the element and then .text, but .find doesn't find the element, why?.

Upvotes: 2

Views: 418

Answers (2)

Avinash Raj
Avinash Raj

Reputation: 174696

You could use BeautifulSoup also.

In [1]: from bs4 import BeautifulSoup

In [2]: xml_as_str = '''
   ...: <v1:Header>
   ...:     <v2:Person>Foo Bar</v2:Person>
   ...:     <v2:Email>[email protected]</v2:Email>
   ...: </v1:Header>
   ...: '''
In [9]: soup = BeautifulSoup(xml_as_str, 'lxml')
In [15]: for i in soup.find_all('v1:header'):
    ...:     for j in soup.find_all('v2:person'):
    ...:         print(j.text)
    ...:         
Foo Bar

In [16]:

Through List-Comprehension.

In [17]: [j.text for i in soup.find_all('v1:header') for j in soup.find_all('v2:person')][0]
Out[17]: 'Foo Bar'

Upvotes: 0

falsetru
falsetru

Reputation: 368894

Using local-name() xpath function:

>>> xml_as_str = '''
... <v1:Header>
...     <v2:Person>Foo Bar</v2:Person>
...     <v2:Email>[email protected]</v2:Email>
... </v1:Header>
... '''
>>>
>>> from lxml import etree
>>> tree = etree.fromstring(xml_as_str, etree.XMLParser(recover=True))
>>> tree.xpath('//*[local-name()="v2:Person"]/text()')[0]
'Foo Bar'

Upvotes: 2

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