CODEWITHSUNDEEP
xpath
Veejay
Veejay

Reputation: 242

Regular Expression to select Hyperlink

I am using the following Expression to select all hyperlinks

//a[@href]

How can I write an expression to select all hyperlinks which match this format

http://abc.com/articles/1

here http://abc.com/articles/ is constant and the article number increases

Upvotes: 0

Views: 1088

Answers (3)

Pavel Nikolov
Pavel Nikolov

Reputation: 9541

<a\s.*?href=(?:["'](http://abc.com/articles/([0-9])+)["']).*?>(.*?)</a>

UPDATE:

If you need the xpath expression here it is:

a[starts-with(@href,'http://abc.com/articles/')]

this would return all the links which has href attribute which starts with 'http://abc.com/articles/' I hope this answers your qiestion.

Upvotes: 1

Brian Roach
Brian Roach

Reputation: 76898

It's a bit overkill, but this is the regex I use in my apps to find URLs in plain text:

(\b(?:(?:https?|ftp|file)://|www\.|ftp\.) (?:\([-A-Z0-9+&@#/%=~|\$\?!:,\.]*\) |[-A-Z0-9+&@#/%=~|\$\?!:,\.])* (?:\([-A-Z0-9+&@#/%=~|\$\?!:,\.]*\) |[A-Z0-9+&@#/%=~|\$]))

Upvotes: 0

mpen
mpen

Reputation: 282865

That expression looks like XPath, not a regex. A regex for that particular URL would look like

^http://abc.com/articles/\d+$

But I guess you'll have to use your xpath query to find the hyperlinks, then filter them based on the HREF attribute using that regex.

Upvotes: 1

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