CODEWITHSUNDEEP
c
Sam Peterson
Sam Peterson

Reputation: 107

Printing the values of specific data types in C?

I'm trying to print out three columns:

Value: Datatype: Size(in bytes):

to the console: 

#include <stdio.h>
/*
print out the primitive (basic built in) data types for C
along with their size in bytes.
*/
int main(){
    char letter = 'j';
    short int x = 55437;
    long int y = 1234567;
    double dbl = 5.99;
    float boobs = 4.66;

    printf("Value:    Datatype:  Size(in bytes):\n\n");

    printf("%c\t  char\t   %c\n", letter, sizeof(letter));
    printf("%d\t  short\t   %d\n", x, sizeof(x));
    printf("%ld\t  long\t   %ld\n", y, sizeof(y));
    printf("%lf\t  double\t   %lf\n", dbl, sizeof(dbl));
    printf("%f\t  float\t   %f\n", boobs, sizeof(boobs));
}

I almost got it, but I'm still having some incorrect output: new problems

Why is my short int printing out as -10099 (contradicting that I had already assigned it to 55437)? And why are my double and float data type specifiers in the Datatype column being shifted so far right?

Upvotes: 0

Views: 158

Answers (3)

user4231709
user4231709

Reputation:

try this :)

printf("%c\t  char\t   %g\n", letter, sizeof(letter));
printf("%d\t  short\t   %g\n", x, sizeof(x));
printf("%ld\t  long\t   %g\n", y, sizeof(y));
printf("%g.2\t  double\t   %g\n", dbl, sizeof(dbl));
printf("%f.2\t  float\t   %g\n", boobs, sizeof(boobs));

Upvotes: 0

BLUEPIXY
BLUEPIXY

Reputation: 40145

try this

printf("%c\tchar\t   %d\n", letter, (int)sizeof(letter));
printf("%hd\tshort\t   %d\n", x, (int)sizeof(x));//55437 > max of int16
printf("%ld\tlong\t   %d\n", y, (int)sizeof(y));
printf("%f\tdouble\t   %d\n", mile, (int)sizeof(mile));
printf("%f\tfloat\t   %d\n", wage, (int)sizeof(wage));

Upvotes: 1

Yu Hao
Yu Hao

Reputation: 122423

When a value is printed with "%c" in printf, it's converted to unsigned char. However, for ASCII, only values ranging from 0x20 to 0x7E are printable characters. How the other characters are shown is up to the terminal.

Upvotes: 1

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