Reputation: 20464
Maths are not my speciality and as this is more a math question than a VB question I tagged it with C# tag too.
I need help to draw a triangle inside the working area (client rectangle) of a custom user control but I fail setting the right coordinates (I fail trying to calculate the right coordinates doing operations with Me.Left, Me.Right, Me.Top and Me.Bottom...), here is the relevant code to draw the rectangle:, but anyways I'm not sure whether I'm using the beast approach (because the control's client rectangle area).
Dim ptsArray As PointF() =
{
New PointF(0, 0),
New PointF(0, 0),
New PointF(0, 0),
New PointF(0, 0)
}
Dim gp As New Drawing2D.GraphicsPath(Drawing2D.FillMode.Alternate)
gp.AddLines(ptsArray)
gp.CloseFigure()
e.Graphics.FillPath(Brushes.Red, gp)
e.Graphics.DrawLines(Pens.Black, ptsArray)
If this is my control:
The rectangle result should be like this, as you'll see the rectangle respects the proportions/size of the control:
Upvotes: 0
Views: 1078
Reputation: 9981
Here's an example of how to draw a triangle. Note that you also need take the width of the pen into the equations. Also, you need to draw the path
, not the lines.
pt1:
top center, pt2:
bottom - right, pt3:
bottom - left.
Using pen As New Pen(Brushes.Red, 10)
Dim rect As Rectangle = Me.ClientRectangle
Dim pt1 As New PointF(CSng(rect.Left + (rect.Width / 2)), (rect.Top + pen.Width))
Dim pt2 As New PointF((rect.Right - pen.Width), (rect.Bottom - pen.Width))
Dim pt3 As New PointF((rect.Left + pen.Width), (rect.Bottom - pen.Width))
Using path As New Drawing2D.GraphicsPath(FillMode.Winding)
path.AddLines({pt1, pt2, pt3, pt1})
path.CloseFigure()
e.Graphics.DrawPath(pen, path)
End Using
End Using
Upvotes: 2