CODEWITHSUNDEEP
jsonscalaplayframework-2.3
Simon
Simon

Reputation: 6462

Render two json objects to the view with Play! scala 2.3

Here is a dumb question : I simply want to render two Json object to the view, I manage to do render them separately but not together...

I tried a simple trick like that (I tried with two '+' as well): 

def totalToPay = Action { 
    Ok(Json.toJson(Account4686.findAllWithCredit()) + Json.toJson(Account403.findAllByOrgaIdWithCredit(1)))
}

but without success. I have this compilation error : [error] /home/sim/dev/ticketapp/app/controllers/Admin.scala:136: type mismatch; [error] found : play.api.libs.json.JsValue [error] required: String.

What is the correct way to perform this?

Upvotes: 2

Views: 899

Answers (1)

Ben Reich
Ben Reich

Reputation: 16324

You can use the JsArray constructor that takes in a Seq[JsValue] as such:

JsArray(Seq(Json.toJson(obj1), Json.toJson(obj2))

Or if you want to use a JsObject instead of an array, you can do:

Json.obj("obj1" -> obj1, "obj2" -> obj2)

To merge two objects, you can use ++:

Json.toJson(obj1).asInstanceOf[JsObject] ++ Json.toJson(obj2).asInstanceOf[JsObject]

Upvotes: 2

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