CODEWITHSUNDEEP
dart
richard
richard

Reputation: 3299

dart url parameters get corrupted

Given the following simple code

Uri url = new Uri.http("localhost:8090", "/browseDirectories",{"path":"\log\fastdmo.localhost.log"});

http.get( url).then( (response) {
    print( response.body);
 });

I find that the http.get() method does not make the correct call on the web server As far as I can see the url becomes

http://localhost:8090/browseDirectories?path=log%0Castdmo.localhost.log

I know this is because the leading \ of the path parameter gets dropped, but how do I prevent that from happening?

Upvotes: 0

Views: 68

Answers (1)

Pixel Elephant
Pixel Elephant

Reputation: 21383

You can use a raw string by prefixing the string with r:

Uri url = new Uri.http("localhost:8090", "/browseDirectories",{"path":r"\log\fastdmo.localhost.log"});

which will result in the following URL:

http://localhost:8090/browseDirectories?path=%5Clog%5Cfastdmo.localhost.log

Alternatively, you can use a second backslash to escape the backslash:

Uri url = new Uri.http("localhost:8090", "/browseDirectories",{"path":"\\log\\fastdmo.localhost.log"});

Upvotes: 2

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