Reputation: 1775
I'm using the new Angular UI Grid (that is planned to replace ng-grid). My data needs some formatting before it's displayed in the table. For instance, my server returns an attribute named "status" as a number, but I want to display it as a nice name.
If status=1 display "Todo", if status=2 display "Doing" etc.
How can this be done in UI Grid?
Upvotes: 1
Views: 5319
Reputation: 146
The shortest way is use CellTemplate with appScopeProvider:
vm.gridOptions = {
columnDefs: [
{
field: 'status',
cellTemplate: '<div>{{grid.appScope.formatStatus(row)}</div>'
}
],
appScopeProvider: {
formatStatus: function (row) {
return row.entity.status === 1 ? 'Todo' : 'Doing';
},
}
}
Upvotes: 1
Reputation: 6650
The preferred method now is to use a cellFilter, rather than a custom template. Custom templates are OK, but they impose more workload on upgrade - you have to check whether new features require modifications to your template.
There is a reasonable example of filters in the tutorials: http://ui-grid.info/docs/#/tutorial/201_editable
Note the cellFilter: 'mapGender'
on the gender column, and the filter itself defined further below in the tutorial:
.filter('mapGender', function() {
var genderHash = {
1: 'male',
2: 'female'
};
return function(input) {
if (!input){
return '';
} else {
return genderHash[input];
}
};
})
Upvotes: 5
Reputation: 2022
First step, add a cellTemplate to the column:
$scope.gridOptions.columnDefs = [
{field:'status', displayName: 'Status',cellTemplate: 'statusTemplate.html'}
];
The Template-File should look like this (COL_FIELD is the actual field):
<div style="text-align: center">{{COL_FIELD==1 ? 'Todo' : 'Doing'"}}</div>
Hope, you got the idea! :)
Upvotes: 2