Reputation: 1470
I am new to jquery
and I am trying to hide certain div
element and then show them on success of my Ajax
call.
When the page loads, browser hides the div
element, on Ajax
success the element is shown, but again browser is hiding the div
elements.
Code
<script>
$(document).ready(function() {
$('#sidebar-container').hide(1000);
$('#overall-status').hide(1000);
$('#submit-date').click(function() {
var processDate = $('#processDate').val();
alert(processDate);
$.ajax({
type : "POST",
url : "launchapptest",
data : processDate,
dataType : "json",
success : function(result) {
alert("Success");
$('#sidebar-container').css({
visibility : "visible"
});
$('#overall-status').css({
visibility : "visible"
});
}
});
}
);
});
</script>
Please help me understand what is happening and how to avoid this.
Upvotes: 3
Views: 1013
Reputation: 3287
.hide()
sets styling to display:none
. You need to call .show()
, instead of .css({visibility:'visible'});
Upvotes: 2
Reputation: 93571
You have to stop the current animation queue for each element first (as non-animated CSS changes will not add to that queue):
Also, as mentioned elsewhere show()
is a better option to css visibility
as hide sets display: none
and not visibility
.
success : function(result) {
alert("Success");
$('#sidebar-container').stop().show();
$('#overall-status').stop().show();
}
Additionally you are possibily not stopping the form from submitting, so the page would reload and rehide the divs. Try stopping the default behavior of that button.
$('#submit-date').click(function(e) {
e.preventdefault()
Upvotes: 2
Reputation: 1470
The issue is resolved, I created a form submit button to initiate the Ajax call. changed it to normal input button. The page was reloading because of this.
I changed the submit button to input button, to resolve this issue.
Thanks a lot for all the help.
Upvotes: 3
Reputation: 2263
Use jquery Show
event.
$(document).ready(function() {
$('#sidebar-container').hide(1000);
$('#overall-status').hide(1000);
$('#submit-date').click(function() {
var processDate = $('#processDate').val();
alert(processDate);
$.ajax({
type : "POST",
url : "launchapptest",
data : processDate,
dataType : "json",
success : function(result) {
alert("Success");
$('#sidebar-container').show();
$('#overall-status').show();
}
});
}
);
});
Upvotes: 4