Reputation: 4632
I'm looking to convert single digit numbers to two-digit numbers like so:
9 ==> 09
5 ==> 05
12 == 12
4 ==> 04
I figure I could put a bunch of if-else statements (if number is under 10, then do a gsub) but figure that's horrible coding. I know Rails has number_with_precision but I see that it only applies to decimal numbers. Any ideas on how to convert single-digits to two-digits?
Upvotes: 131
Views: 65609
Reputation: 732
Rubocop recommends format
over sprintf
and %
. I think it's more intuitive:
format('%02d', 7) # => "07"
format('%02d', 12) # => "12"
Upvotes: 2
Reputation: 47472
Try this, it should work:
abc = 5
puts "%.2i" % abc # => 05
abc = 5.0
puts "%.2f" % abc # => 5.00
Upvotes: 12
Reputation: 107718
A lot of people using sprintf
(which is the right thing to do), and I think if you want to do this for a string it's best to keep in mind the rjust
and ljust
methods:
"4".rjust(2, '0')
This will make the "4"
right justified by ensuring it's at least 2
characters long and pad it with '0'
. ljust
does the opposite.
Upvotes: 216
Reputation: 59927
how about "%02d" % 9
? see http://www.ruby-doc.org/core-2.0/String.html#method-i-25 and http://www.ruby-doc.org/core-2.0/Kernel.html#method-i-sprintf .
Upvotes: 35
Reputation: 258138
Did you mean sprintf '%02d', n
?
irb(main):003:0> sprintf '%02d', 1
=> "01"
irb(main):004:0> sprintf '%02d', 10
=> "10"
You might want to reference the format table for sprintf
in the future, but for this particular example '%02d'
means to print an integer (d
) taking up at least 2 characters (2
) and left-padding with zeros instead of spaces (0
).
Upvotes: 157