CODEWITHSUNDEEP
regex
Szymon Toda
Szymon Toda

Reputation: 4516

Regex - digits after string not greedy

Data to work with is ...deliveryProfilID: 22261,offerID: '83627489',productKindID: '2',...

It's irregular string from which I have to pull digits of offerID

So I need regex to return 83627489

I got working one but it's awful: offerID\s{0,}:\s{0,}'(\d*)'\s{0,}

I want to use something like this: offerID.*(\d*) but it selects to much.

Upvotes: 0

Views: 34

Answers (2)

John Sobolewski
John Sobolewski

Reputation: 4572

offerID[\s]*:[\s]*'(\d*)'

is probably more readable?

but as sp00m said...

offerID\s*:\s*'(\d)'

is already better.

and Avinash Raj's suggestion of

offerID[\D]*(\d*)'

might be my favorite but the brackets aren't necessary.

offerID\D*(\d*)'

Works too.

Upvotes: 0

Yu Hao
Yu Hao

Reputation: 122383

A little modification would work:

offerID\D*(\d*)

Unlike .*, \D* only matches non-digits. And of course you can further improve it if needed:

offerID:\D*'(\d*)'

Upvotes: 1

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