Reputation: 143
my program in R creates an n-dimensional array.
PVALUES = array(0, dim=dimensions)
where dimensions = c(x,y,z, ... )
The dimensions will depend on a particular input. So, I want to create a general-purpose code that will:
From reading this site I learned how to do #2 - read an element from the array
ll=list(x,y,z, ...)
element_xyz = do.call(`[`, c(list(PVALUES), ll))
Please help me solving #1, that is storing an element to the n-dimensional array.
Let me rephrase my question
Suppose I have a 4-dimensional array. I can store a value and read a value from this array:
PVALUES[1,1,1,1] = 43 #set a value
data = PVALUES[1,1,1,1] #use a value
How can I perform the same operations using a function of a vector of indexes:
indexes = c(1,1,1,1)
set(PVALUES, indexes) = 43
data = get(PVALUES, indexes) ?
Thank you
Upvotes: 1
Views: 1508
Reputation: 143
Thanks for helpful response.
I will use the following solution:
PVALUES = array(0, dim=dimensions) #Create an n-dimensional array
dimensions = c(x,y,z,...,n)
Set a value to PVALUES[x,y,z,...,n]:
y=c(x,y,z,...,n)
PVALUES[t(y)]=26
Reading a value from PVALUES[x,y,z,...,n]:
y=c(x,y,z,...,n)
data=PVALUES[t(y)]
Upvotes: 1
Reputation: 263332
The indexing of arrays can be done with matrices having the same number of columns as there are dimensions:
# Assignment with "[<-"
newvals <- matrix( c( x,y,z,vals), ncol=4)
PVALUES[ newvals[ ,-4] ] <- vals
# Reading values with "["
PVALUES[ newvals[ ,-4] ]
Upvotes: 0