Reputation: 66174
I often have classes that are mostly just wrappers around some STL container, like this:
class Foo {
public:
typedef std::vector<whatever> Vec;
typedef Vec::size_type size_type;
const Vec& GetVec() { return vec_; }
size_type size() { return vec_.size() }
private:
Vec vec_;
};
I am not so sure about returning size_type
. Often, some function will call size()
and pass that value on to another function and that one will use it and maybe pass it on. Now everyone has to include that Foo header, although I'm really just passing some size value around, which should just be unsigned int
anyway ...? What is the right thing to do here? Is it best practice to really use size_type
everywhere?
Upvotes: 4
Views: 2571
Reputation: 43380
One option you could consider is inheriting from std::vector
:
typedef std::vector<whatever> Foo_Vec;
class Foo : public Foo_Vec
{
public:
const Foo_Vec &GetVec() { return (Foo_Vec&)*this; }
};
I am by no means saying this is the best approach, as it can introduce issues that wouldn't occur by having a private member or inheriting from private Foo_Vec
, as public Foo_Vec
exposes all methods on std::vector
to Foo
. Moreover, std::vector
does not have a virtual destructor, so if you attempt to clean up a collection of std::vector
's with a Foo tucked in there, it won't get cleaned up entirely. I'm just throwing it out there.
As other answers suggest, you should use size_t
or size_type
instead of unsigned int
for 64-bit compatibility. Otherwise, in a future 64-bit build, your std::vector
could have more than 232 items, but the size value would be truncated, leading to bugs.
Upvotes: -1
Reputation: 41331
I am not so sure about returning size_type. Often, some function will call size() and pass that value on to another function and that one will use it and maybe pass it on. Now everyone has to include that Foo header...
It's fine to return the size_type
, but this doesn't mean another function should necessarily take the same size_type
as typedeffed in your class. There exist conversions between integral types. Be brave and just use size_t
.
You can't overload functions anyway so that there would be one that works with size
of vector, another for size of deque
etc, just in case they all happen to be using a different size_type
(which the standard probably permits). - But you could also use templates, if possible, to deduce the correct size_type
to use from the argument.
Upvotes: 1
Reputation: 503855
It should be vector<>::size_type
like you have, this is the most correct way.
That said, I know many people, including myself, will just use size_t
instead. Although it's not mandated to be the same, vector<>::size_type
is size_t
for every implementation I know. You should be fine with that.
Upvotes: 8
Reputation: 41096
STL defines these types as an abstract interface for containers. It is intended to support any type of backing storage. That might be NUMA or disk-backed storage, where size_type
and ptr-type
are different from those for system memory. Or - in a NUMA architecture - it might be a specific memory node that's fast, and can work with a very small size_type
and ptr_type
- which is a relevant optimization on many architectures.
At least, that were the design goals, also driven by anticipation what could be platforms supporting C++. Some early concessions also allowed shortcuts for STL implementers that basically disable this flexibility, and I've never worked with an STL implementation that made use of this. I'd say that's because linear memory access has become much less of a problem, and STL development at that level isn't actually easy.
Still, how much does it hurt you? It would be the right thing to do.
Upvotes: 7
Reputation: 43311
Actually, it should be size_t and not unsigned int, for 64-bit compatibility. As wrapper class writer, I would return size_type. As class client, I would cast it to appropriate type (size_t), if it is more convenient.
Upvotes: 5