CODEWITHSUNDEEP
java
Louie Morris
Louie Morris

Reputation: 55

Displaying word letter by letter

How would I do this?

Give me a word > sugar

s

su

sug

suga

sugar

Here is what I have so far:

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter a word:");
    String word = scan.nextLine();
    int length = word.length();
    for(int number = 0; number < length; number++){
        System.out.println(word.charAt(number));
    }
}

This makes the word display letter by letter.

Upvotes: 0

Views: 108

Answers (2)

Alex K
Alex K

Reputation: 8338

I would suggest using String.substring(int startIndex, int endIndex).

For you, your program would look like this:

String s = "Sugar";
for(int i = 0; i < s.length() - 1; i++) {
    System.out.println(s.substring(0,i)); 
}

Keep in mind that startIndex is inclusive, endIndex is exclusive. So "Sugar".substring(0,3) will give "Sug".

Upvotes: 4

MadProgrammer
MadProgrammer

Reputation: 347314

One approach would be to use a form of String concaternation...

String word = "Sugar";
int length = word.length();
StringBuilder sb = new StringBuilder(word.length());
for (int number = 0; number < length; number++) {
    sb.append(word.charAt(number));
    System.out.println(sb.toString());
}

Basically, this appends each character to the builder on each loop, printing the results...

S
Su
Sug
Suga
Sugar

Another approach might be to use a compound loop...

String word = "Sugar";
int length = word.length();
for (int number = 0; number < length; number++) {
    for (int inner = 0; inner < number; inner++) {
        System.out.print(word.charAt(inner));
    }
    System.out.println("");
}

The outer (first) loop controls the number of characters you want to print, the inner (second) loop physically prints each character from the start to the number of characters you want to print...(nb: This will print a leading empty space, so you might need a if in there to control that if it's important)

Upvotes: 3

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