Reputation: 311
exist "ex/try.groovy", i try:
println "ls -al |grep try".execute(null, new File("/home/roroco/Dropbox/jvs/ro-idea/ex")).text
it didn't output anything
but when i try following, it will output "try.groovy"
roroco@roroco ~/Dropbox/jvs/ro-idea/ex $ cd /home/roroco/Dropbox/jvs/ro-idea/ex;ls -al |grep try
-rw-r--r-- 1 roroco roroco 95 Nov 17 17:28 try.groovy
my question is how to make groovy output is same with terminal
Upvotes: 0
Views: 185
Reputation: 37008
you can not use |
here as it is handled by the shell. either use sh -c
to execute or pipe yourself. See http://groovy.codehaus.org/Process+Management
def p = ['sh', '-c', 'ls /tmp | grep groovy'].execute()
p.waitFor()
println p.text
or
def p1 = 'ls /tmp'.execute()
def p2 = 'grep groovy'.execute()
p1 | p2
p2.waitFor()
println p2.text
Upvotes: 2