CODEWITHSUNDEEP
python
vorsicht t
vorsicht t

Reputation: 33

how to split based on space instead of new line?

I have the following code which removes the "refs/changes/digit" but am not getting the expected output,i have the curent output as shown below,can anyone provide inputs on how to fix this?

source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
output = ' '.join(line.split('/', 3)[-1] for line in source.splitlines())
print output


CURRENT OUTPUT:-

1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2

expected output

1025744/3 1025962/5 913745/2

Upvotes: 1

Views: 65

Answers (2)

Padraic Cunningham
Padraic Cunningham

Reputation: 180401

split on whitespace then split on the first three "/" and extract the last element. 

source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
print(" ".join([ele.split("/",3)[-1] for ele in source.split()]))
1025744/3 1025962/5 913745/2

some timings:

In [3]: import re

In [4]: timeit " ".join([ele.split("/",3)[-1] for ele in source.split()])
100000 loops, best of 3: 1.83 µs per loop

In [5]: timeit p.findall(source)

100000 loops, best of 3: 2.84 µs per loop

Upvotes: 2

syntagma
syntagma

Reputation: 24324

Another approach would be to use regular expression:

import re
p = re.compile(r'(\d{6,7}/\d{1})')
source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
print p.findall(source)

Note that I explicitly define number before slash to be 6 or 7 characters long (you can adjust regexp to your needs).

Upvotes: 1

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