CODEWITHSUNDEEP
javajqueryspringspring-mvc
Abhishek Singh
Abhishek Singh

Reputation: 9765

Spring MVC ajax call a controller using

@RequestMapping(value = "downloadFIReport.do", method = RequestMethod.POST)
 public @ResponseBody String downloadFIBill(ModelMap model,@ModelAttribute("SpringWeb") FIReportSearchInput fiReportSearchInput)
{

//

}

Above is my controller code. I want to send FIReportSearchInput fiReportSearchInput as input without binding it to page using a <form:form/> tag and using jQuery's Ajax method

$.ajax()

How can this be done ?

Update here is the definition of FIReportSearchInput 

public class FIReportSearchInput {
    @DateTimeFormat(pattern = "dd/MM/yyyy")
    private Date startDate;
    @DateTimeFormat(pattern = "dd/MM/yyyy")
    private Date endDate;

    public Date getStartDate() {
        return startDate;
    }
    public void setStartDate(Date startDate) {
        this.startDate = startDate;
    }
    public Date getEndDate() {
        return endDate;
    }
    public void setEndDate(Date endDate) {
        this.endDate = endDate;
    }



}

Upvotes: 2

Views: 3657

Answers (1)

maniac
maniac

Reputation: 36

Here is a example,you can try it: I suppose FIReportSearchInput have id and name attributes.

$.ajax({
  url:"downloadFIReport.do",
  type:"post",
  dataType:"json",
  data:{id:$("#id").val(),name:$("#name").val()},
  success:function(){}
});

when the spring mvc server catch this request,if your answer body is 'FIReportSearchInput fiReportSearchInput' and Object FIReportSearchInput have id and name attributes,it will call setter method automatically to build a new FIReportSearchInput Object named fiReportSearchInput.

Upvotes: 2

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