CODEWITHSUNDEEP
pythonlistdictionarycompare
Umar Farooq
Umar Farooq

Reputation: 331

Comparing values in a dictionary to values in a list

Basically, the program checks if the rhyming pattern of a poem is correct. I've taken the parameter of ['A', 'B', 'A'] and arranged it in a dictionary that has the index of words to compare. 

rhyme_pattern = {'A': [0, 2], 'B': [1]}

I've also taken the last word from each line and put that into a list. 

words_to_compare = ['OFF', 'NEXT', 'ENDS']

And I've made a helper function that compares two words and if they rhyme. I can't figure out how to loop through rhyme_pattern['A'] and compare the words 'OFF' and 'ENDS'. Also, I then get the problem of not comparing anything if there is only one index value, like B.

Upvotes: 0

Views: 105

Answers (3)

ely
ely

Reputation: 77404

You can use dict.get(some_val, []) to ensure that an empty list is returned if some_val doesn't appear in the dict:

rhyme_pattern.get('A', [])

and then write your helper function so that it behaves as expected when an entry has just the empty list.

Assuming your comparison function is called compare_with, then you can compare with the elements in dict['A'] like this:

[compare_with(x, y) for x in rhyme_pattern.get('A', []) 
                    for y in words_to_compare]

This last bit assumes your comparison function works like compare_with(0, 'OFF'). If instead you are looking to index into words_to_compare via the contents of rhyme_pattern['A'], it might look like this:

A_words = [word_to_compare[x] for x in rhyme_pattern.get('A', [])]

Upvotes: 1

Padraic Cunningham
Padraic Cunningham

Reputation: 180391

rhyme_pattern = {'A': [0, 2], 'B': [1]}
words_to_compare = ['OFF', 'NEXT', 'ENDS']
for val in rhyme_pattern["A"]:
    print(words_to_compare[val])

To access all values iterate over the values:

for val in rhyme_pattern.itervalues(): # just .values() for python 3
    print([words_to_compare[v] for v in val])

This presumes that all the values will be in the index range of words_to_compare which from your question seems to be the case.

Upvotes: 1

fizzyh2o
fizzyh2o

Reputation: 1319

You need to loop through rhyme_pattern and compare all values in any array with more than 1 value. The hard part is getting all combinations of words to compare. the itertools library makes this easy.

This should work:

import itertools as it  
for words in rhyme_pattern:
        if len(words) > 1:
             #now loop through all combinations of 2 words
             for pair in it.permutations(words,2):
                 if not words_ryhme(*pair):
                    return False
return True

Upvotes: 1

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