CODEWITHSUNDEEP
pythonlistbooleancounting
Victor
Victor

Reputation: 65

Boolean value of a list

I made a function and my result is a list:

[3, 3, 3]

Now I need to return a boolean value. If all of the elements are 2 or higher, I need to return True otherwise I need to return false. In this case it would be : True. ( Because all the elements are 3 and 3 > 2) Is there any code to do this quickly?

I tried to make a FOR - loop like:

for i in [3, 3, 3]: if i >= 2: return True else: return False

I think this is correct but I want to know if there is a faster method.

thanks in advance!

Upvotes: 0

Views: 143

Answers (3)

vaultah
vaultah

Reputation: 46533

Make a generator (generator expression here) that yields booleans and pass it to all function:

>>> all(x >= 2 for x in [3, 3, 3])
True

I see you posted your code, it's not correct as it will only check the first element of the list. You can fix it:

for i in your_list: 
    if i < 2: 
        return False # Return early
return True # if `i < 2` was False for all elements in the list, return True

Upvotes: 4

Alex
Alex

Reputation: 467

def areGreaterEqualThen2(lst):
    if lst:
        return lst[0] >= 2 and areGreaterEqualThen2(lst[1:])
    return True

If you have to define your own function.

It also is a fast solution because if the first condition is false, the entire and returns false.

Upvotes: 0

Gabriel
Gabriel

Reputation: 3584

a= [3, 3, 3]
b=[elem for elem in a if elem > 2]  
print (a==b)

Output: True

or in a more condensed way

a= [3, 3, 3]
print([elem for elem in a if elem > 2]==a)

Output: True

Upvotes: 0

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