CODEWITHSUNDEEP
stringscala
user3370773
user3370773

Reputation: 455

Scala strings - how to change lines

I'm trying to create an informative report according to results. I currently have a .foreach loop iterating over a list, and writes the report.

The code looks like:

result.foreach {
    tupleResult =>
      tupleResult._3 match {
        case "FirstTest" =>
          language1 = createReport(tupleResult)
        case "SecondTest" =>
          language2 = createReport(tupleResult)
        case "ThirdTest" =>
          language3 = createReport(tupleResult)
      }
      finalReport = ""
  }

Each "createReport" is a method which creates a one line String into the relevant language var. I want each iteration to add a different line in the "finalReport" string.

Example of "finalReport":

Report consists of the following:
1) language1
2) language2
3) language3

The question is how to create the different variables as different lines of the same "finalReport" string.

Upvotes: 0

Views: 223

Answers (2)

elm
elm

Reputation: 20415

Associating an ordering to the test strings may prove a solution, for instance like this,

val ord = Array("FirstTest","SecondTest","ThirdTest").zipWithIndex.toMap

Then we can generate the parts of the report, and finally sort them by the defined ordering,

val finalReport = result.map { tRes => (ord.get(tRes._3), createReport(tRes)) }
  .sortBy(_._1)
  .map(_._2)
  .mkString("\n")

Upvotes: 1

johanandren
johanandren

Reputation: 11479

The more idiomatic scala way to do it would be to not do several things at once and also mutate state, but instead see it as separate operations/expressions. Something like this for example:

val sortedResults = result.sortBy(_._3 match {
  case "FirstTest" => 1
  case "SecondTest" => 2
  case "ThirdTest" => 3
})

val reportLines = sortedResults.map(result => createReport(result._3))

val finalReport = reportLines.mkString("\n")

Upvotes: 2

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