CODEWITHSUNDEEP
javascriptjqueryregexmatch
ditto
ditto

Reputation: 6277

Match Regex: [everything before number], [number]

I'm using a .match() on a bunch of strings that vary quite a bit. I'm wanting to get the last number inside a bracket from the string, and from there get everything before that. So for example:

1 serving  (57.0 g)
1 slice, small (2" x 2-1/2" x 1-3/4")  (32.0 g)

Becomes an array of:

['1 serving', '57.0 g']
['1 slice, small (2" x 2-1/2" x 1-3/4")', '32.0 g']

A list of the various strings: http://regex101.com/r/jJ5sF3/1

I've struggling to write a regex that captures this.

Upvotes: 2

Views: 3326

Answers (4)

huwence
huwence

Reputation: 326

Try this regex string, I could run it in regex101 for your case. 

/(.+)\s\((.+)\)/g

Upvotes: 0

vks
vks

Reputation: 67968

(.*)\s(\([^)]*\))

Try this.See demo.

http://regex101.com/r/jJ5sF3/3

var re = /(.*)\s(\([^)]*\))/g;
var str = '71 oz (28.4 g)\n1 slice, small (2" x 2-1/2" x 1-3/4") (32.0 g)\n1 slice, small (29.0 g)\n81 oz (28.4 g)\n1 pita, large (6-1/2" dia) (64.0 g)\n21 cup, crumbs (45.0 g)\n61 oz (28.4 g)\n1 cup (108.0 g)\n61 oz (28.4 g)\n1 cup, crumbs (45.0 g)\n41 oz (28.4 g)\n1 serving (57.0 g)\n1 100 g (100.0 g)\n71 oz (28.4 g)\n1 slice, small (2" x 2-1/2" x 1-3/4") (32.0 g)\n1 slice, small (29.0 g)\n81 oz (28.4 g)\n1 pita, large (6-1/2" dia) (64.0 g)\n181 oz (28.4 g)\n21 cup, crumbs (45.0 g)\n61 oz (28.4 g)\n1 cup (108.0 g)\n131 oz (28.4 g)\n1 cup, crumbs (45.0 g)\n1 serving (50.0 g)\n1 100 g (100.0 g) \n1 slice, small (2" x 2-1/2" x 1-3/4") (32.0 g) \n1 slice, small (29.0 g) \n1 pita, large (6-1/2" dia) (60.0 g) \n21 cup, crumbs (45.0 g) \n1 cup (108.0 g) \n131 oz (28.4 g) \n61 oz (28.4 g) \n1 cup, crumbs (45.0 g) \n41 oz (28.4 g) \n1 serving (50.0 g) \n1 100 g (100.0 g';
var m;

while ((m = re.exec(str)) != null) {
if (m.index === re.lastIndex) {
re.lastIndex++;
}
// View your result using the m-variable.
// eg m[0] etc.
}

Upvotes: 0

alpha bravo
alpha bravo

Reputation: 7948

use this pattern 

(.*\S)\s*\(([^()]+)

Demo

(               # Capturing Group (1)
  .             # Any character except line break
  *             # (zero or more)(greedy)
  \S            # <not a whitespace character>
)               # End of Capturing Group (1)
\s              # <whitespace character>
*               # (zero or more)(greedy)
\(              # "("
(               # Capturing Group (2)
  [^()]         # Character not in [^()]
  +             # (one or more)(greedy)
)               # End of Capturing Group (2)

Upvotes: 4

Arun P Johny
Arun P Johny

Reputation: 388316

Try a regex like

/(.*?)\s*\(([.\d\sg]*?)\)\s*$/gmi
  • (.*?) - group all the characters before the last () set
  • \s*\( - separate the spaces after the text content and (
  • ([.\d\sg]*?) group the contents inside the last ()

Upvotes: 0

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