user3501587
user3501587

Reputation: 425

HTML5 / Jquery upload - debug code, because proble.m with rewriting files

UPDATED

How i can hold added files by input field?

I created this script: http://jsfiddle.net/dyzg9qa8/1/

jQuery(document).ready(function() {

    $('input').on('change', function(event) {

        var img = this.files;
        var show = '.s_' + $(this).attr("class");

        $.each(img, function(index, f) {
            var reader = new FileReader();

            reader.onload = function(e){
                $('<img src="' + e.target.result + '" width="450">').appendTo(show);
            }

            reader.readAsDataURL(f);
        });
    });
});

and html:

<form method="post" enctype="multipart/form-data">

    <label for="images">Multiple Images</label>
    <input type="file" class="img1" name="img[]" multiple accept="image/*">
    <div class="s_img1"></div>

    <hr>

    <label for="images">Multiple Images</label>
    <input type="file" class="img2" name="img[]" multiple accept="image/*">
    <div class="s_img2"></div>

    <input type="submit" value="Send">

</form>

when for eg. I add two images to the input will be displayed below, and as I click again on the input and I will add one more picture of this will be added to these two below. So now I have 3 pictures below.

but when I type in php "print_r" in the form displays only the last value of the input. in $_FILES only is submit last value of input. I want send all values added before, how to do this ? :)

regards!

Upvotes: 0

Views: 67

Answers (1)

Sunhat
Sunhat

Reputation: 137

the name="" attribute is what defines the variable name in PHP.

So having two tags with name="img" will make the 2nd overwrite the first.

You'll need to do one of the following:

name="img[]"

This makes the name img an array and when PHP receives it, it can foreach through img

or you can do name="img1" and name="img2" for PHP to pick them up separately.

You should also be using the $_FILES['img'] variable to access files (including images) uploaded to the server.

Upvotes: 2

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