CODEWITHSUNDEEP
python
FreeSteampowresGames
FreeSteampowresGames

Reputation: 303

Is there a simple way to process an html form upload with python?

As we all know the simplest way to upload a file in php is with this code : 

<form action="upload.php" method="post" enctype="multipart/form-data">
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload File" name="submit">
</form>

I want a method to upload a file with python the simplest as possible, a file from the current directory like this: 

import anyuploadmodule
upload(file)

Is there a such module can do this ?

Upvotes: 1

Views: 3288

Answers (1)

xj9
xj9

Reputation: 3471

There isn't anything quite that simple out there, but micro-frameworks like Flask can be lightweight and simple starting points. You'll want to checkout the documentation. Here's a snippet to get you started:

# -*- coding: utf-8 -*-

import os

from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename

app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = '/some/path/'

@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        file = request.files['file']
        filename = secure_filename(file.filename)
        file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
        return redirect(url_for('uploaded_file', filename=filename))
    return '''<!doctype html>
              <title>Upload new File</title>
              <h1>Upload new File</h1>
              <form action="" method=post enctype=multipart/form-data>
                <p><input type=file name=file>
                <input type=submit value=Upload>
              </form>'''

if __name__ == '__main__':
    app.run()

Upvotes: 3

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