CODEWITHSUNDEEP
pythondjangoloopstemplates
gamer
gamer

Reputation: 5863

django print only one value in for loop in template

I want to display only one value from for loop in template. Let's say I have this:

{% for category in categories %}
    {{category.name}}
    <a href="{% url "my_url" category.id %}">See All</a>
{% endfor %}

If I have 5 category then See All in being printed 5 times. How can I only print it once.. Thanx in adnvance..

Upvotes: 0

Views: 4460

Answers (4)

Himanshu dua
Himanshu dua

Reputation: 2523

This code will print the first element in Category 

    {% for category in categories %}
        {% if categories | first %}  
            {{category.name}}
            <a href="{% url "my_url" category.id %}">See All</a>
        {% endif %}

    {% endfor %}

Upvotes: 0

wolendranh
wolendranh

Reputation: 4292

Not the best way but check this:

{% for category in categories %}
    {% if categories|length > 1 %}
        <a href="{% url "my_url" category.id %}">See All</a>
    {% else %}
        {{categories[1].name}}
        <a href="{% url "my_url" category.id %}">{{category.name}}</a>
    {% endif %}
{% endfor %}

Upvotes: 0

Fumbo
Fumbo

Reputation: 110

You should have a main page with all your categories in which you will send it context['categories']

And if you don't need to have a link between your categories in detail just send the current category in the views.py :

context['category']

EDIT: If all you want to do is break in the loop you can't in django template but you can use slice :

{% for category in categories|slice:":1" %}

It will just go through the loop once

Upvotes: 2

Raja Simon
Raja Simon

Reputation: 10305

You have to limit the object and send that object to template 

tempalte_var['content'] = Categories.objects.all()[:5]

Upvotes: 0

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