CODEWITHSUNDEEP
phpsession
Justin
Justin

Reputation: 49

check if session exist and has specific value


i'm trying to check if a session exist and has a specific value (2) to show a part of the website and if not it should return you to a other page.

So far i got this: 

$_SESSION["deel"] = "2";  //set session deel to 2
$result = array("error" => false, "html" => null);
$result["error"] = false;
$result["html"] = "<h3>Session information:";
$result["html"] .= "<a href='/shop/?,69'>$_SESSION[class2C]</a>";
$result["html"] .= "</h3>";

after that we go to a other page:

if (!isset($_SESSION['deel']) || $_SESSION['deel'] == '2')
{ show the shit }
else 
{ redirect }

However, it doesn't do anything and just shows me "the shit"
what am i doing wrong here?

Thanks in advance.

Upvotes: 0

Views: 331

Answers (1)

Hanky Panky
Hanky Panky

Reputation: 46900

Your condition is wrong

if (!isset($_SESSION['deel']) || $_SESSION['deel'] == '2')
    ^                         ^^

Means if the session is not set or if it is set then the value is 2, This will be true even if there is no session. You should do:

if (isset($_SESSION['deel']) && $_SESSION['deel'] == 2)

This can also be derived from your own statement

i'm trying to check if a session exist and has a specific value (2)

                      ^       ^          ^
 if (isset($_SESSION['deel']) &&  $_SESSION['deel'] == 2)

Upvotes: 2

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