CODEWITHSUNDEEP
pythonargparse
user3654650
user3654650

Reputation: 6103

How to iterate over arguments

I have such script:

import argparse

parser = argparse.ArgumentParser(
                description='Text file conversion.'
                )
parser.add_argument("inputfile",   help="file to process", type=str)
parser.add_argument("-o", "--out", default="output.txt",
                    help="output name")
parser.add_argument("-t", "--type", default="detailed",
                    help="Type of processing")

args = parser.parse_args()

for arg in args:
    print(arg)

But it doesnt work. I get error:

TypeError: 'Namespace' object is not iterable

How to iterate over arguments and their value?

Upvotes: 91

Views: 63547

Answers (7)

James Sapam
James Sapam

Reputation: 16930

Add vars if you want to iterate over a Namespace object:

 for arg in vars(args):
     print arg, getattr(args, arg)

Upvotes: 143

Christophe Biocca
Christophe Biocca

Reputation: 3468

Namespace objects aren't iterable, the standard docs suggest doing the following if you want a dictionary:

>>> vars(args)
{'foo': 'BAR'}

So

for key, value in vars(args).items():
    # do stuff

To be honest, I am not sure why you want to iterate over the arguments. That somewhat defeats the purpose of having an argument parser.

Upvotes: 37

rdbreak
rdbreak

Reputation: 11

Using the builtin dict() class to iterate over the args is straightforward and works great:

args = parser.parse_args()
args_dict = dict(vars(args))
for i, ii in args_dict.items():
     print(i, ii)

From builtins.py:

    def __init__(self, seq=None, **kwargs): # known special case of dict.__init__
        """
        dict() -> new empty dictionary
        dict(mapping) -> new dictionary initialized from a mapping object's
            (key, value) pairs
        dict(iterable) -> new dictionary initialized as if via:
            d = {}
            for k, v in iterable:
                d[k] = v
        dict(**kwargs) -> new dictionary initialized with the name=value pairs
            in the keyword argument list.  For example:  dict(one=1, two=2)
        # (copied from class doc)
        """
        pass

Upvotes: 1

BoboDarph
BoboDarph

Reputation: 2891

Parsing the _actions from your parser seems like a decent idea. Instead of running parse_args() and then trying to pick stuff out of your Namespace.

import argparse

parser = argparse.ArgumentParser(
                description='Text file conversion.')
parser.add_argument("inputfile", help="file to process", type=str)
parser.add_argument("-o", "--out", default="output.txt",
                help="output name")
parser.add_argument("-t", "--type", default="detailed",
                help="Type of processing")
options = parser._actions
for k in options:
    print(getattr(k, 'dest'), getattr(k, 'default'))

You can modify the 'dest' part to be 'choices' for example if you need the preset defaults for a parameter in another script (by returning the options in a function for example).

Upvotes: 3

mork
mork

Reputation: 1863

I'm using args.__dict__, which lets you access the underlying dict structure. Then, its a simple key-value iteration:

for k in args.__dict__:
  print k, args.__dict__[k]

Upvotes: 4

hpaulj
hpaulj

Reputation: 231335

After

args = parser.parse_args()

to display the arguments, use:

print args # or print(args) in python3

The args object (of type argparse.Namespace) isn't iterable (i.e. not a list), but it has a .__str__ method, which displays the values nicely.

args.out and args.type give the values of the 2 arguments you defined. This works most of the time. getattr(args, key) the most general way of accessing the values, but usually isn't needed.

vars(args)

turns the namespace into a dictionary, which you can access with all the dictionary methods. This is spelled out in the docs.

ref: the Namespace paragraph of the docs - https://docs.python.org/2/library/argparse.html#the-namespace-object

Upvotes: 9

Victor Wong
Victor Wong

Reputation: 2486

ArgumentParser.parse_args returns a Namespace object instead of an iterable arrays.

For your reference, https://docs.python.org/3/library/argparse.html#parsing-arguments

ArgumentParser parses arguments through the parse_args() method. This will inspect the command line, convert each argument to the appropriate type and then invoke the appropriate action.

And it is not supposed to be used like that. Consider your use case, in the doc, it says argparse will figure out how to parse those out of sys.argv., which means you don't have to iterate over those arguments.

Upvotes: 0

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