CODEWITHSUNDEEP
jakarta-eeejb
Sush
Sush

Reputation: 317

How Exceptions are handle in EJB?

I have written following code for exception handling of EJB.

1)Module.java

`@WebService(serviceName = "Module")
@Stateless()
public class Module {
    /**
     * This is a sample web service operation
     */
    @WebMethod(operationName = "hello")
    public int hello(@WebParam(name = "name") String txt) throws Exception {
        int re=0;
        try{
            re=(6/0);     
        }catch(Exception e){
            throw (EJBException) new EJBException(se).initCause(e);
        }
        return re;;
        }
    }
}`

2) Client.jsp

`<%
try{
    selec.Module_Service service = new selec.Module_Service();
    selec.Module port = service.getModulePort();
    java.lang.String name = "";
    int result = port.hello(name);
    out.println("Result = "+result);
}catch(EJBException e){
    Exception ee=(Exception)e.getCause();
    if(ee.getClass().getName().equals("Exception")){
       System.out.println("Database error: "+ e.getMessage());
    }
}
%>`

Inside catch block Exception object ee get me as null. What is an issue that it give me null value

Upvotes: 4

Views: 331

Answers (1)

kolossus
kolossus

Reputation: 20691

You're not using the recommended method to retrieve the root-cause exceptions from an EJB. EJBException#getCausedBy() is the recommended method for getting the root exception on an EJB.

According to the API however, it's even better if you get the cause from Throwable#getCause. So what you should have is 

Exception ee= ((Throwable)e).getCause();

Upvotes: 2

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