CODEWITHSUNDEEP
java
user2884009
user2884009

Reputation: 35

cant make this delimiter work, java split

I need help making a delimiter for multiple characters

I need a String delimiter for these characters

( ) " ; : , ? ! .

I've tried:

private String delimiter = "()\":;,?!.";
private String delimiter = "[()\":;,?!.]";
private String delimiter = "\\(\\)\"\\:\\;\\,\\?\\!\\.";

Seems I can only make them work one at a time.. Any insight is greatly appreciated.

If it matters this is how its going into array:

foo = line.split(delim);

Upvotes: 1

Views: 49

Answers (3)

A4L
A4L

Reputation: 17595

Almost there with nr. 3

@Test
public void delim() {
    String delimiter = "[\\(\\)\"\\:\\;\\,\\?\\!\\.]";
    String[] split = "Hello(World)How:are;You;doing,today?You!sir.I mean"
       .split(delimiter);
    System.out.println(Arrays.toString(split));
}

Output

[Hello, World, How, are, You, doing, today, You, sir, I mean]

You missed the square brackets.

To avoid all the quoting you may use Pattern#quote

String delimiter = "[" + Pattern.quote("()\":;,?!.") + "]";

Returns a literal pattern String for the specified String. This method produces a String that can be used to create a Pattern that would match the string s as if it were a literal pattern. Metacharacters or escape sequences in the input sequence will be given no special meaning.

Upvotes: 3

Ruslan Ostafiichuk
Ruslan Ostafiichuk

Reputation: 4722

| is required between:

delimiter = "\\(|\\)|\"|:|;|,|\\?|!|\\."

Upvotes: 2

August
August

Reputation: 12568

If you want to split on any of those characters, you can separate each one with an alternation: |. Otherwise, the string will only be split when all of those characters are present.

String delimiter = "\\(|\\)|\"|\\:|\\;|\\,|\\?|\\!|\\.";

Also, you're unnecessarily escaping a few characters, this would also work:

String delimiter = "\\(|\\)|\"|:|;|,|\\?|!|\\.";

Upvotes: 3

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