CODEWITHSUNDEEP
javareflection
Aamir
Aamir

Reputation: 2422

Java Reflection Class

Why is second SOP showing output as true here, I was hoping it would display false like first SOP ?

public class reflect1 {

  public static void main(String[] args) {

       Reflect1A obj1 = new Reflect1A();
       Reflect1A obj2 = new Reflect1A();

       System.out.println(obj1 == obj2);

       Class c1 = obj1.getClass();
       Class c2 = obj2.getClass();

       System.out.println(c1 == c2);

       } 
  }

class Reflect1A {

}

Upvotes: 0

Views: 165

Answers (6)

Abhinav Yalamanchili
Abhinav Yalamanchili

Reputation: 51

The operator == compares the references in which the objects are created by default

Obj1 and Obj2 are of same type class Reflect1. For these objects are equal only when compared like this obj1.equal(obj2).

While the class type of obj1 and obj2 are the same == operation will be true.

Upvotes: 0

Sotirios Delimanolis
Sotirios Delimanolis

Reputation: 280168

From the Java Language Specification

  • The method getClass returns the Class object that represents the class of the object.

A Class object exists for each reference type. It can be used, for example, to discover the fully qualified name of a class, its members, its immediate superclass, and any interfaces that it implements.

Since both your objects are of type Reflect1A, they both return the same Class object.

You would get the same object by doing 

Class<?> clazz = Class.forName("com.example.Reflect1A")
System.out.println(c1 == clazz); // true

(though this is not necessarily required by all classloaders.)

Upvotes: 3

Jon Skeet
Jon Skeet

Reputation: 1503489

The values of obj1 and obj2 refer to different objects - when you use == in Java and both operands are references, the result is to compare whether those references refer to the exact same object. In this case you've got two different objects, so the references are not the same.

However, they're both of the same class, so that's why c1 == c2 is true.

Upvotes: 3

alampada
alampada

Reputation: 2409

Because obj1 and obj2 are different instances (first check is false) of the same type (class - second check is true).

https://docs.oracle.com/javase/7/docs/api/java/lang/Object.html#getClass%28%29

why did you expect to return false?

Upvotes: 0

ControlAltDel
ControlAltDel

Reputation: 35106

An object is equal (==) only to itself. So clearly both getClass() statements are returning the same Class object

Upvotes: 1

Adam
Adam

Reputation: 36743

The first line prints false because it is a different instance of the same class.

The second line prints true because it is the same class type. There is a obscure gotcha here to be aware of, if you're in a multiple classloader environment, e.g. an application server like JBoss, or OSGI etc, it is possible for two class instances to not be equal

Upvotes: 1

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