CODEWITHSUNDEEP
xmlvb.netserialization
theB3RV
theB3RV

Reputation: 924

Deserialize XML string to Object VB.NET

I've seen plenty of examples online but either I cannot make sense of the application or the example is too different from mine for me to transpose. I have a XML

<Interfaces>
    <Interface>
        <InterfaceCode>987</InterfaceCode>
        <AccessID>asdf</AccessID>
        <Password>654321</Password>
    </Interface>
    <Interface>
        <InterfaceCode>789</InterfaceCode>
        <AccessID>      </AccessID>
        <Password>      </Password>
    </Interface>
</Interfaces>

And the following classes 

<Serializable(), XmlRoot("Interfaces"), XmlType("Interfaces")>
Public Class InterfacesModel
    Property Interfaces As New List(Of InterfaceModel)
End Class

<Serializable(), XmlType("Interface")>
Public Class InterfaceModel
    Property InterfaceCode As String
    Property AccessID As String
    Property Password As String
End Class

The following code produces a InterfacesModel with an empty Interfaces list:

Dim str As String = xmlString
Dim interfaces As InterfacesModel

Dim serializer As New XmlSerializer(GetType(InterfacesModel))
Using reader As TextReader = New StringReader(str)
     interfaces = serializer.Deserialize(reader)
End Using

I would expect it to populate Interfaces as a List(of InterfaceModel) so that I can perform a for each on Interfaces and do something to each Interface.

Upvotes: 4

Views: 28783

Answers (2)

Zero Point Programming
Zero Point Programming

Reputation: 39

When im writing serializable classes i dont use tags i just use something like this and it works the same

<Serializable>
Public Class Interfaces
    Public interface as InterfaceModel() 'The () Defines an array of InterFaceModels
End Class

<SerialzableAttribute>
Public Class InterfaceModel
    Public InterFaceCode As String
    Public AccessID As String
    Public Password As String
End Class

Upvotes: 0

Uber Schnoz
Uber Schnoz

Reputation: 140

You need XmlElement("Interface") on your property. Also, you can get rid of the XmlType attributes. I don't think those are doing anything for you.

<Serializable(), XmlRoot("Interfaces")>
Public Class InterfacesModel
    <XmlElement("Interface")> Property Interfaces As New List(Of InterfaceModel)
End Class

<Serializable()>
Public Class InterfaceModel
    Property InterfaceCode As String
    Property AccessID As String
    Property Password As String
End Class

Upvotes: 6

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