Reputation: 18745
Is there a command such as break
and continue
which could repeat recent iteration?
For example, when exception is thrown.
for i in range(0,500):
try:
conn = getConnection(url+str(i))
doSomething(conn)
except:
repeat
Let's have an iteration where i
variable's value is 6
. During this iteration some connection error occurred. I want to repeat this iteration.
Is there a command which can do that?
Of course I can do this:
i=0
while i!=500:
try:
conn = getConnection(url+str(i))
doSomething(conn)
i+=1
except:
pass
Upvotes: 25
Views: 38981
Reputation: 99081
Here's a different approach that returns the function with arguments in case of exception:
retries = 0
max_retries = 5
def x(a, b):
global retries
global max_retries
print(retries)
try:
d = a / b
except:
retries += 1
if retries >= max_retries:
return {}
else:
return x(a, b)
a = 0
b = 0
y = x(a, b)
print(y)
0
1
2
3
4
{}
Upvotes: 0
Reputation: 417
Here is one. You would need to add a logging or alert system to let you know that something is stuck:
state = "" #state of the loop
# If there is no error continue. If there is error, remain in loop
while True:
if state != "error":
try:
1/0 # command
break # no error so break out of loop
except:
state = "error" #declare error so maintain loop
continue
elif state == "error": # maintain loop
continue
Upvotes: 0
Reputation: 77407
You can use nested for loops to put a cap on the number of times you retry the operation. This is bascially the sam as @PierreAlex's generator answer but without the extra function definition.
for i in range(500):
for retry in range(10):
try:
conn = getConnection(url+str(i))
doSomething(conn)
except Exception: # Replace Exception with something more specific.
time.sleep(1)
else:
print "iteration", i, "failed"
Upvotes: 1
Reputation: 6386
for i in range(500):
while True
try:
conn = getConnection(url+str(i))
break
except Exception: # still allows to quit with KeyboardInterrupt
continue
do_your_stuff()
This looks bit risky, however, you should at least enable some logging inside a while
block.
If you expect to use it in more places, you might write a simple decorator:
def keep_trying(fn, *args, **kwargs):
def inner(*args, **kwargs):
while True:
try:
return fn(*args, **kwargs)
except Exception:
continue
return inner
# later you can use it simple like this:
for i in range(500):
conn = keep_trying(getConnection)(url+str(i))
Upvotes: 4
Reputation: 473
You can use generators :
def process_connections(n_connections, url, max_tries=50):
i = 0
try_count = 0
while i < n_connections:
try:
conn = getConnection(url+str(i))
yield conn
except:
try_count += 1
if try_count > max_tries:
raise Exception("Unable to connect after %s tries" % max_tries)
else:
i += 1 # increments only if no exception
And you perform your operations :
for conn in process_connections(500, url):
do_something(conn)
Upvotes: 2
Reputation:
No, there is no command to "rewind" a for-loop in Python.
You could use a while True:
loop inside the for-loop:
for i in range(500):
while True:
try:
conn = getConnection(url+str(i))
doSomething(conn)
except Exception: # Replace Exception with something more specific.
continue
else:
break
or without the else:
:
for i in range(500):
while True:
try:
conn = getConnection(url+str(i))
doSomething(conn)
break
except Exception: # Replace Exception with something more specific.
continue
But I personally think that your proposed solution is better because it avoids an indentation level.
Upvotes: 24
Reputation: 14296
Why not just use an if
statement?
n=6
i=0
while i!=500:
failed = False;
try:
conn = getConnection(url+str(i))
doSomething(conn)
i+=1
except:
#handle error
failed = True;
#try again if n-th case failed first time
if(i == n and failed):
try:
conn = getConnection(url+str(i))
doSomething(conn)
except:
#handle error
Upvotes: 0